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Ksivusya [100]
3 years ago
11

Which of the follow tables do not show a linear function

Mathematics
2 answers:
valina [46]3 years ago
6 0
C , i dont know if it’s right but it’s the only table with the same number on the bottom . and same number in general
aleksklad [387]3 years ago
4 0

Answer:

I think its B

Step-by-step explanation:

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When running a 100 meter race Bill reaches his maximum speed when he is 45 meters from the starting line and 5 seconds have elap
Mkey [24]

Bill's speed is constant after 5 seconds and 45 meters into the race.

Correct responses:

a. Bill's maximum speed is 8 m/s

b. 24 meters

c. 57 meters

<h3>Methods used to calculate speed and distance traveled</h3>

Given parameters are;

The distance of the race = 100 meter

Distance at which Bill reaches maximum speed = 45 meters

Speed Bill maintains after 5 seconds = The maximum speed

Time at which Bill is 85 meters from the starting line = 10 seconds after start

a. Required;

Bill's maximum speed in meters.

Solution:

Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m

Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s

Speed = \mathbf{\dfrac{Distance}{Time}}

Therefore;

  • Bill's \  maximum \ speed = \dfrac{40 \ m}{5 \ s} = \underline{8 \ m/s}

b. i. Required:

The distance Bill will run for 3 seconds at the maximum speed;

Solution:

Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>

<em />

The distance traveled at maximum speed in 3 seconds is therefore;

Distance = 8 m/s × 3 s = 24 m

The distance Bill travels in 3 seconds at the maximum speed is 24 meters.

ii) The distance Bill travels at 8 seconds after start, is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 3 seconds = 24 meters

Therefore;

  • Bill's distance from the starting line 8 seconds after start is 45 meters + 25 meters = <u>69 meters</u>

c. Bill's distance 6.5 seconds after the start of the race is given as follows;

Distance traveled in the first 5 seconds = 45 meters

Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters

  • Bill's distance from the starting line 6.5 seconds after start of the race = 45 meters + 12 meters = <u>57 meters</u>

Learn more about distance, speed, time, relationship here:

https://brainly.in/question/49075584

6 0
1 year ago
What is 4/7 + 2/7 in simplest form
Arada [10]
\frac{2}{7} +\frac{4}{7}\\&#10;\frac{2+4}{7}\\&#10;\frac{6}{7}
Your answer is \frac{6}{7}
3 0
3 years ago
Convert the following measurements into
Andre45 [30]

Answer:

1) 1076.4ft^2

2). 6561.68ft

3). 2.057kg

4). 1.25×10^-1

5). 6.58×10^1km

6). 278mg

6 0
2 years ago
Does anyone know how to do this?? steps are helpful but not necessary
aniked [119]

Answer:

C.  \frac{2(x+16)}{x+4}

Step-by-step explanation:

We want fg of x, so first we have to multiply f(x) times g(x).

\frac{x+16}{x} * \frac{2x}{x+4}

\frac{(x+16)2x}{x(x+4)}

\frac{2x^{2}+32x}{x^{2}+4x}

We can cancel out an x from every term.

\frac{2x+32}{x+4}

Let's rewind a little to get this into one of the answer choices.

\frac{2(x+16)}{x+4} is our answer.

6 0
3 years ago
Triangle A″B″C″ is formed by a reflection over x = −1 and dilation by a scale factor of 4 from the origin. Which equation shows
juin [17]

Answer:

\frac{AB}{A''B''}  = \frac{1}{4}

Step-by-step explanation:

Given the information:

  • A'B'C' reflection over x = −1
  • dilation by a scale factor of 4 from the origin

<=> the two triangles are similar to each other, triangles are similar if they have the same shape, but can be different sizes, so  A″B″C″ is 4 time bigger than ABC

=> the relationship between ΔABC and ΔA″B″C″

= \frac{AB}{A''B''}  = \frac{1}{4}

We choose C.

Hope it will find you well.

7 0
3 years ago
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