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trasher [3.6K]
3 years ago
12

1/2(x-6.5) = 3.16 what is x?

Mathematics
2 answers:
Aleks04 [339]3 years ago
6 0

Answer: 12.82

Step-by-step explanation:

1/2(x-6.5)= 3.16

x=12.82

cricket20 [7]3 years ago
5 0

Answer:

x =12.82

Step-by-step explanation:

1/2(x-6.5) = 3.16

Multiply each side by 2

1/2(x-6.5) *2 = 3.16 *2

(x-6.5) = 6.32

Add 6.5 to each side

(x-6.5+6.5) = 6.32+ 6.5

x =12.82

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Answer:

C)   −2.2y−1.8

Step-by-step explanation:

1.2y+4.5-3.4y-6.3=

Combine Like terms:

=−2.2y−1.8

6 0
3 years ago
Which of the following equations represents a graph with the least rapid rate of change? A. Y= 3 (3^x) B. Y= 5 (2^x) C. Y= 2 (5^
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3 years ago
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Step-by-step explanation:

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3 years ago
What is 12 1/3-10 11/12
Brut [27]

Answer:

1 5/12

Step-by-step explanation:

12 1/3 - 10 11/12

We need to get a common denominator of 12

12 1/3 * 4/4 - 10 11/12

12 4/12 - 10 11/12

We need to borrow from the 12 (the whole number)  because the 2nd fraction is bigger than the first

12 becomes 11 and the 1 becomes 12/12

11+ (12/12 + 4/12) - 10 11/12

11 16/12 - 10 11/12

Subtract the whole numbers

11-10 =1

Subtract the fractions

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5 0
4 years ago
Use cramers Rule to solve the following system:
Jet001 [13]

Answer:

The solution to the system is x=1,y=-2 and z=-5

Step-by-step explanation:

Cramer's rule defines the solution of a system of equations in the following way:

x= \frac{D_x}{D}, y= \frac{D_y}{D} and z= \frac{D_z}{D} where D_x, D_y and D_z are the determinants formed by replacing the x,y and z-column values with the answer-column values respectively. D is the determinant of the system. Let's see how this rule applies to this system.

The system can be written in matrix form like:

\left[\begin{array}{ccc}5&-3&1\\0&2&-3\\7&10&0\end{array}\right]\times \left[\begin{array}{c}x&y&z\end{array}\right] = \left[\begin{array}{c}6&11&-13\end{array}\right]

Then each of the previous determinants are given by:

D_x = \left|\begin{array}{ccc}6&-3&1\\11&2&-3\\-13&10&0\end{array}\right|=199 Notice how the x-column has been substituted with the answer-column one.

D_y = \left|\begin{array}{ccc}5&6&1\\0&11&-3\\7&-13&0\end{array}\right|=-398 Notice how the y-column has been substituted with the answer-column one.

D_z = \left|\begin{array}{ccc}5&-3&6\\0&2&11\\7&10&-13\end{array}\right|=-995

Then, substituting the values:

x= \frac{D_x}{D}=\frac{199}{199}\\ x=1

x= \frac{D_y}{D}=\frac{-398}{199}\\ y=-2

x= \frac{D_z}{D}=\frac{-995}{199}\\ x=-5

3 0
3 years ago
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