Answer:
candles = $400
matches = $20
Step-by-step explanation:
Let cost of candles = $c
Let cost of matches = $m
c = 20 m (20 times m)
c + m = 420
20m + m = 420
21 m = 420
m = 20
c = 20 (20) = 400
Answer:
<em>$528</em>
Step-by-step explanation:
A. Calculating The Markdown Price
X=Markdown price
Original price: $600
Markdown rate: 20%
100%-20%=80%
The TV's price is now 80% of what it originally was.

100x=48000
x=480
The price of the TV after being marked down is $480.
B. Calculating The Sales Tax
Y=Total sales tax
TV price: $480
Sales tax: 10% or 0.1
y=480*0.1
y=48
The total sales tax is $48
C. Calculating Your Total
x+y=total
480+48=total
total=528
You in total pay $528 for the TV.
5,309 divided by 43 is equal to 123.4651162790698
Answer:
The probability that the aircraft is overload = 0.9999
Yes , The pilot has to be take strict action .
Step-by-step explanation:
P.S - The exact question is -
Given - Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.
To find - What is the probability that the aircraft is overloaded ?
Should the pilot take any action to correct for an overloaded aircraft ?
Proof -
Given that,
Mean, μ = 182.7
Standard Deviation, σ = 39.6
Now,
Let X be the Weight of the men
Now,
Probability that the aircraft is loaded be
P(X > 168 ) = P(
)
= P( z >
)
= P( z > -0.371)
= 1 - P ( z ≤ -0.371 )
= 1 - P( z > 0.371)
= 1 - 0.00010363
= 0.9999
⇒P(X > 168) = 0.9999
As the probability of weight overload = 0.9999
So, The pilot has to be take strict action .
3-5w+12+2w-3
(3+12-3)=12
(-5w+2w)=-3w
-3w+12