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Elena-2011 [213]
2 years ago
13

A company orders 29 boxed lunches from a deli for $324.80. If each boxed lunch

Mathematics
1 answer:
UkoKoshka [18]2 years ago
3 0

Answer:

Each boxed lunch costs $11.20

Step-by-step explanation:

29 boxed lunches = $324.80

divide by 29 on each one

1 boxed lunch = $11.20

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Solve the equation x2 = 10.
MatroZZZ [7]

Answer:

\large\boxed{x=-\sqrt{10}\ or\ x=\sqrt{10}}

Step-by-step explanation:

x^2=10\iff x=\pm\sqrt{10}

8 0
2 years ago
How do I solve for x?
Marina CMI [18]
Multiply both sides by 2
7 0
2 years ago
Which expression plzzzz helpppppppp
lara31 [8.8K]
Answer is D

sum of constants = 8 + 4 = 12
sum of coefficients = 7 + 3 = 10

12 > 10  
7 0
3 years ago
How many solutions does this equation have?
drek231 [11]

The answer is infinitely many solutions because 0 = 0.

If you don't seem to see where I got 0 = 0, look at the equation,

4b – 4b = 0

first lets do the math on the left side.

4b - 4b  is equal to 0.

so lets put 0 on the left side, now lets look at the equation all together,

0 = 0,

and this means that it has infinitely many solutions.

The reason why it is not no solution because no solution means when there are no answers to the equation. For example, the solution is not true, such as the equation 24 ≠ 29. This is a no solution equation. One solution can be 4x = 20, as x = 5, concluding it being one solutions.

5 0
2 years ago
Can somebody please help me with question b please?
snow_tiger [21]
\bf A=
\begin{bmatrix}
-2&0\\1&3
\end{bmatrix}\qquad B=
\begin{bmatrix}
1&0&3\\-1&3&0
\end{bmatrix}\\\\
-----------------------------\\\\
AB=
\begin{bmatrix}
(-2\cdot 1)+(0\cdot -1)&(-2\cdot 0)+(0\cdot 3)&(-2\cdot 3)+(0\cdot 0)\\\\
(1\cdot 1)+(3\cdot -1)&(1\cdot 0)+(3\cdot 3)&(1\cdot 3)+(3\cdot 0)
\end{bmatrix}

as you notice above, is the first-row components from A, multiplying all the columns subsequently on B, and you add the products of that row, that gives you one component on the AB matrix

in the one above, we end up with a 2x3 AB matrix
4 0
3 years ago
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