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morpeh [17]
3 years ago
5

Please help!!!! please help!!!!!​

Mathematics
2 answers:
shutvik [7]3 years ago
7 0

Answer:

1. True

2. Hundreds

Step-by-step explanation:

1. Natural numbers are positive integers (whole numbers) 1, 2, 3, etc. 0 is lower than all of them.

2. 3 (ten thousands), 0 (thousands), 8 (hundreds), 4 (tens), 6 (ones). Try reading out the number.

Nata [24]3 years ago
6 0
[True]

Natural numbers are the positive integers (whole numbers) such as 1, 2, 3, and etc. So it is true that zero is less than every natural number.

[Hundreds]

The 8 in 30,846 is in the hundreds place because the 8 stands for 800.
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Anon25 [30]

We can complete the square to rewrite h(t) as

3+20t-5t^2=23-5(t-2)^2

Then solve for when h(t)=8:

23-5(t-2)^2=8\implies15=5(t-2)^2

\implies(t-2)^2=3

\implies t-2=\pm\sqrt3

\implies t=2\pm\sqrt3

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The line representing a proportional relationship always goes through the point (0,0). If x is zero, multiplying x by the consta
Sidana [21]

Answer:

B (2, 4)

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem the constant of proportionality k is given and is equal to

k=2

so

The linear equation is given by

y=2x

That means ----> the y-coordinate is two times the x-coordinate

therefore

The other point is B(2.4)

Because

For x=2, y=4

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3 years ago
I need help to answer this question
mr_godi [17]
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(c). Under a set of controlled laboratory conditions, the size of the population P of a certain bacteria culture at time t (in s
Bezzdna [24]

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P(1) = 3•1² + 3e¹ + 10 = 13 + 3e ≈ 21.155

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P[t_] := 3t^2 + 3E^t + 10

(E is case-sensitive and must be capitalized. Alternatively, you could use Exp[t]. You can also specify that the argument t must be non-negative by entering a condition via P[t_ ;/ t >= 0], but that's not necessary.)

Then just evaluate P[1], or N[P[1]] or N <at symbol> P[1] or P[1] // N to get a numerical result.

(ii) The average rate of change of P(t) over an interval [a, b} is

(P(b) - P(a))/(b - a)

Then the ARoC between t = 2 and t = 6 is

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In M,

(P[6] - P[2])/(6 - 2)

and you can also include N just as before.

(iii) You want the instantaneous rate of change of P when t = 60 (since 1 minute = 60 seconds). Differentiate P :

P'(t) = 6t + 3e^t

Evaluate the derivative at t = 60 :

P'(60) = 6•60 + 3e⁶⁰ = 360 + 3e⁶⁰

The approximate value is quite large, so I'll just leave its exact value.

In M, the quickest way would be P'[60], or you can differentiate and replace (via ReplaceAll or /.) t with 60 as in D[P[t], t] /. t -> 60.

5 0
3 years ago
What is the decimal 3.4 written in word form
Rama09 [41]

Answer:

three and four tenths

Step-by-step explanation:

7 0
3 years ago
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