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Eduardwww [97]
3 years ago
5

If a pair of pants costs $30.00 and is marked 15% off, what is the sale price

Mathematics
1 answer:
belka [17]3 years ago
5 0
$25.50
15% of 30 is 4.5 which if you subtract it'll make $25.50 <span />
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3) Scenario 1 Scenario 2 y = 50x x is time in hours y is distance in miles Compare the scenarios and determine which shows the g
Olegator [25]

Answer:

Option A.

Step-by-step explanation:

Consider the below figure attached with this question.

Scenario 1 represented by the graph.

From the graph it is clear that the line passes through the points (1,60) and (2,120).

Slope of the line is

y=\dfrac{y_2-y_1}{x_2-x_1}

y=\dfrac{120-60}{2-1}=60

The slope of line is 60. It means the speed is 60 miles per hour.

Scenario 2 defined by the equation,

y=50x

If an equation defined as y=mx+b, then m is slope and b is y-intercept.

m=50

The slope of line is 50. It means the speed is 50 miles per hour.  

The slope of Scenario 1 is greater than slope of Scenario 2. So, the Scenario 1 shows the greater speed.

Hence, the correct option is A.

6 0
3 years ago
Read 2 more answers
PLS HELPP MEE The question is in the picture below
kotegsom [21]
Im pretty sure it would be $60. If im wrong im sorryyyyy
8 0
3 years ago
Read 2 more answers
Write the equation of a line that is perpendicular to y=5 and that passes through the point (−7,−5)
nordsb [41]

x =  - 7 \\  \\ hope \: it \: helps

6 0
2 years ago
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Please give real answers with an explaination. I will follow + I will give the brainliest. No Docs/No Files/No Links, only answe
Rufina [12.5K]

Answer:

134

Step-by-step explanation:

the line where B and X are equal to 180 so you subtract 180 from B witch is 134

6 0
3 years ago
Suppose M is the midpoint of line FG.
alukav5142 [94]
A)\\|FM|=5y+13;\ |MG|=5-3y\\\\|FG|=|FM|+|MG|\\\\|FG|=(5y+13)+(5-3y)=2y+18\\\\B)\\|FM|=8a+1;\ |FG|=42\\\\|FG|=2|FM|\\\\2(8a+1)=42\\16a+2=42\ \ \ \ \ |subtract\ 2\  from\ both\ sides\\16=40\ \ \ \ \ |divide\ both\ sides\ by\ 16\\a=\frac{40}{16}\\a=\frac{5}{2}\\a=2.5

6 0
3 years ago
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