Answer:
x= 6 ± √31
Step-by-step explanation:
x^2-12x=-5
x^2 -12x +36= -5 +36
(x -6)^2= 31
√(x -6)^2= ±√31
(x-6)= ±√31
x= 6 ± √31
Answer:
well x-(-18) x+18 but the if part is x<-18 will stay the same
Step-by-step explanation:
So all you need to do is subtract m from both sides.
Then you have your answer
m = 1
I hope this helps
-ayden
Answer:
A) X=pi/2 or X=-pi/2
B) X=pi/6 or X=-pi/6
C) X=pi/4 , 3pi/4, 5pi/4 and 7pi/4
D) X= 1-cos^2(x/2)
E) X= pi/3 +2pi N, 5pi/3+2pi N
Step-by-step explanation:
Don't even bother asking. :)
Here i how I would do it:<span>f(x)=−<span>x2</span>+8x+15</span>
set f(x) = 0 to find the points at which the graph crosses the x-axis. So<span>−<span>x2</span>+8x+15=0</span>
multiply through by -1<span><span>x2</span>−8x−15=0</span>
<span>(x−4<span>)2</span>−31=0</span>
<span>x=4±<span>31<span>−−</span>√</span></span>
So these are the points at which the graph crosses the x-axis. To find the point where it crosses the y-axis, set x=0 in your original equation to get 15. Now because of the negative on the x^2, your graph will be an upside down parabola, going through<span>(0,15),(4−<span>31<span>−−</span>√</span>,0)and(4+<span>31<span>−−</span>√</span>,0)</span>
To find the coordinates of the maximum (it is maximum) of the graph, you take a look at the completed square method above. Since we multiplied through by -1, we need to multiply through by it again to get:<span>f(x)=31−(x−4<span>)2</span></span><span>
Now this is maximal when x=4, because x=4 causes -(x-4)^2 to vanish. So the coordinates of the maximum are (4,y). To find the y, simply substitute x=4 into the equation f(x) to give y = 31. So it agrees with the mighty Satellite: (4,31) is the vertex.</span>
