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White raven [17]
2 years ago
11

The area if a rectangular frame is 32 square inches. The perimeter of the frame is 24 inches. Which shows the correct dimensions

of the frame?
Mathematics
1 answer:
Zarrin [17]2 years ago
8 0

Answer:

8 x 4

Step-by-step explanation:

Lets say the length is x and the width is y.

xy = 32

2x + 2y = 24

Rearranging the second equation, we get:

2x = 24 - 2y

/2         /2

x = 12 - y

substitute into the first equation

y(12 - y) = 32

12y - y^2 = 32

-32             -32

-y^2 +12y - 32 = 0

x -1                      x -1

y^2 - 12y + 32 = 0

(y - 8)(y - 4) = 0

y = 8 or 4

substitute into x = 12 - y.

x = 12 - 8 = 4

x = 12 -4 = 8

so the correct dimensions are 4 x 8, as either x = 4 and y =8, or x = 8 and y = 4.

Hope I helped!

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The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
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Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

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So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches)  = P(X bar < 30.35) - P(X bar <= 30.25)

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Therefore, P(30.25 inches < X bar < 30.35 inches)  = 0.99865 - 0.97725

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