Answer:
The home would be worth $249000 during the year of 2012.
Step-by-step explanation:
The price of the home in t years after 2004 can be modeled by the following equation:

In which P(0) is the price of the house in 2004 and r is the growth rate.
Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.
This means that 
$172000 in 2004
This means that 
What year would the home be worth $ 249000 ?
t years after 2004.
t is found when P(t) = 249000. So







2004 + 8.05 = 2012
The home would be worth $249000 during the year of 2012.
As x = 5 & z=12,
<span>2/3 = y /(xz) = y/(5*12) </span>
<span>= y/60 </span>
<span>so y / 60 = 2/3 </span>
<span>y = (2*60)/3 </span>
<span>= 40</span>
That is distributive property ... hope this helps
Perimeter is all sides added<span />