So it (-6-22)+(321) ? Before I solve this problem?
If the value of a is negative, then the range will be (-∞, k) and if the value of the a is positive then the range will be (k, ∞).
<h3>What is a quadratic equation?</h3>
It's a polynomial with a worth of nothing.
There exist polynomials of variable power 2, 1, and 0 terms.
A quadratic condition is a condition with one explanation where the degree of the equation is 2.
Domain and range of linear and quadratic functions
Let the linear equation be y = mx + c.
Then the domain and the range of the linear function are always real.
Let the quadratic equation will be in vertex form.
y = a(x - h)² + k
Then the domain of the quadratic function will be real.
If the value of a is negative, then the range will be (-∞, k) and if the value of the a is positive then the range will be (k, ∞).
More about the quadratic equation link is given below.
brainly.com/question/2263981
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C the bank will exchange his new car for a old one
Answer:
(-6,1) (2,7)
Step-by-step explanation:
y =x+5
y = x^2 +5x-7
Set the two equations equal since y=y
x+5 = x^2 +5x -7
Subtract x from each side
x-x+5 = x^2 +5x-x -7
5 = x^2 +4x -7
Subtract 5 from each side
5-5 = x^2 +4x -7-5
0 = x^2 +4x-12
Now we can factor the right side
What 2 numbers multiply to -12 and add to +4
6*-2 =-12
6-2 =4
0 = (x+6) (x-2)
Using the zero product property
x+6=0 x-2=0
x=-6 x=2
We need to find y for each value of x
y = x+5 y = x+5
y = -6+5 y = 2+5
y =1 y = 7
Answer:
The correct answer would be the bottom equation.
Step-by-step explanation:
y=7.25x
y=7.25(3)
y=21.75
y=7.25(4)
y=29.00
y=7.25(5)
y=36.25
