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2 years ago

What is the completely factored form of x2 – 16xy 64y2? xy(x – 16 64y) xy(x 16 64y) (x – 8y)(x – 8y) (x 8y)(x 8y)

Mathematics

1 answer:

Alja [10]2 years ago

3 0

The complete factored form of the quadratic expression is (x-8y)(x-8y)

<h3>Factorizing quadratic expression</h3>

Quadratic expressions are expressions that has a leading degree of 2

Given the expression

x^2 – 16xy + 64y^2

Factorize

x^2 - 8xy - 8xy + 64y^2

Group

(x^2 - 8xy) - (8xy + 64y^2)

x(x-8y) - 8y(x - 8y)

Since (x-8y) is common, hence;

x^2 - 8xy - 8xy + 64y^2 = (x-8y)(x-8y)

The complete factored form of the quadratic expression is (x-8y)(x-8y)

Learn more on factoring here: brainly.com/question/65494

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Write the fraction<br> in simplest form.<br> 42/49

lozanna [386]

Answer:

6/7 is the ans

42 & 49 is divided by 7

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3 years ago

If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.

oksian1 [2.3K]

Answer:

$NK = 15$

$JL = 26$

$KL = 19.85$

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

Step-by-step explanation:

Given

$MK = 30$

$NL = 13$

$\angle MKL = 41$

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

$NK = \frac{1}{2} * MK$

$NK = \frac{1}{2} * 30$

$NK = 15$

Solving (b): JL

JL is a diagonal, and it is twice of NL.

$JL = 2 * NL$

$JL = 2 * 13$

$JL = 26$

Solving (c): KL

To solve for KL, we consider triangle KNL where:

$\angle KNL = 90$

and

$KL^2 = NL^2 + NK^2$

$KL^2 = 13^2 + 15^2$

$KL^2 = 394$

$KL = \sqrt{394$

$KL = 19.85$

Solving (d - h):

To do this, we consider triangle JKN

$\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90$ -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

$\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41$

Similarly:

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41$

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49$

So:

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = \angle MLJ + \angle JLK$

$\angle MLK = 49 + 41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

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