Answer:
x = 2 cm
y = 2 cm
A(max) = 4 cm²
Step-by-step explanation: See Annex
The right isosceles triangle has two 45° angles and the right angle.
tan 45° = 1 = x / 4 - y or x = 4 - y y = 4 - x
A(r) = x* y
Area of the rectangle as a function of x
A(x) = x * ( 4 - x ) A(x) = 4*x - x²
Tacking derivatives on both sides of the equation:
A´(x) = 4 - 2*x A´(x) = 0 4 - 2*x = 0
2*x = 4
x = 2 cm
And y = 4 - 2 = 2 cm
The rectangle of maximum area result to be a square of side 2 cm
A(max) = 2*2 = 4 cm²
To find out if A(x) has a maximum in the point x = 2
We get the second derivative
A´´(x) = -2 A´´(x) < 0 then A(x) has a maximum at x = 2
Answer:
First term a₁ = 3/2 and common ratio r = 2
Step-by-step explanation:
We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96
Since common ratio is required so, the sequence is geometric sequence
The formula used is: 
We are given: third term = 6 i,e

Seventh term = 96

Dividing eq(2) and eq(3)

So, Common Ratio r = 2
Finding First term using eq(1)

So, First term a₁ = 3/2 and common ratio r = 2
Answer:
Step-by-step explanation:
50,000 mm=5,000 cm=500 decimeter=50 m=5 decameter
so both are equal.
I’m not 100% sure kind of a guess but I would x=2/3. Good luck