(One steel rod’s volume) = 3.14 x 4^2 x 20
= 1004.8cm^3
(Used steel) / (One steel rod’s volume) =
(Made steel rod’s number)
The answer is 28
Answer:
The answer I got was D 215605/1000
1-2. The best estimate for the population mean would be sample mean of 60 gallons. Since we know that the sample mean is the best point of estimate. Since sample size n=16 is less than 25, we use the t distribution. Assume population from normal distribution.
3. Given a=0.1, the t (0.05, df = n – 1 = 15)=1.75
4. xbar ± t*s/vn = 60 ± 1.75*20/4 = ( 51.25, 68.75)
5. Since the interval include 63, it is reasonable.
Answer:
728
Step-by-step explanation:
2+6+18+...+486
a=2
r=6/2=3
