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lina2011 [118]
2 years ago
14

Let’s go I need help on number 9 I’ll give you brainliest

Mathematics
1 answer:
Nitella [24]2 years ago
4 0
Answer is 24. Hopefully your talking abt the one that starts with (-5)
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What pair of points have a slope of -3/5
sergey [27]

Answer:

(5,0) and (0,3) have a slope of -3/5

Step-by-step explanation:

Here, we want to state a pair of points that have a slope of -3/5

Mathematically, we can have the slope of a straight line calculated as;

m = y2-y1/(x2-x1)

This could give points like (5,0) and (0,3)

3 0
2 years ago
I will mark you the brainiest for the correct answer, please be correct, Have a good day and take care, thanks. ( VIEW THE IMAGE
Gwar [14]
First error is that the legs are a and b so a should be x and b is 6 and c is 10 the second error is at the end they did not take the square root to get x by itself the real answer should be
X^2 +6^2=10^2
X^2+36=100
X^2 =64
X=8
6 0
2 years ago
In a science class, 40% of the students received a grade of A, 30% received a grade of B, and 20% received a grade of C on a pro
8090 [49]

Answer:

30 students are in the science class and 3 students recieved a failing grade.

7 0
3 years ago
Read 2 more answers
Simplify (8x^3-5x-1)-(7x^2+6x-10)
irakobra [83]

Answer:

8x^3-7x^2-11x+9

Step-by-step explanation:

(8x^3-5x-1)-(7x^2+6x-10)

remove unnesasary ( )

8x^3-5x-1 -(7x^2+6x-10)

the distribute

8x^3-5x-1 -7x^2-6x+10

combine like terms

8x^3-11x+9-7x^2

use the communative property to reorder the equation

8x^3-7x^2-11x+9

4 0
2 years ago
HELP ASAP
astra-53 [7]

Answer:

Step-by-step explanation:

We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:

Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:

5^2 = 3^2 + x^2

x = 4

The radius is 4 + 1 cm = 5 cm

So the area of the circle is A = pi*r^2

A = 3.14 * (5)^2  

A = 25pi cm^2

To solve for the area of the shaded region:

Ashaded = Acircle - Atriangles

we need to solve for the area of the triangles:

A = 1/2 *b*h

A = 1/2 *6 * 5

A = 15 cm^2

Atriangles = 2 * 15  

Atriangles = 30 cm^2

Ashaded = 25pi - 30

8 0
2 years ago
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