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FrozenT [24]
3 years ago
6

Solve the absolute value equation 3x+2=2

Mathematics
2 answers:
babunello [35]3 years ago
8 0

Answer:

0

Step-by-step explanation:

3x+2=2

or, 3x=2-2

or, x=0/3

:. x=0

Deffense [45]3 years ago
6 0

Answer:

3x=2-2

or,3x=0

so,x=0/3

so x=0

Step-by-step explanation:

when + goes on right side it becomes -

and solving it

and 3x means 3 × x so when it goes on right side it becomes divides

and 0/3 is 0

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Does anyone know how to simplify this -4i(2+3i)???
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4i

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-4i(2+3i)

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3 years ago
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Quadrilateral RJFT is similar to quadrilateral SYPA . JF=60 mm , AP=40 mm , and YP=25 mm . What is TF ?
Hoochie [10]
The two quadrilaterals are similar. Which means the ratios of respective sides of two quadrilaterals will be the same. 

So, for the given quadrilaterals, ratio of sides JF and TF of quadrilateral RJFT will be equal to the ratio of sides YP and AP of quadrilateral SYPA. Mathematically, we can write:

JF:TF = YP:AP \\  \\ 
 \frac{JF}{TF} = \frac{YP}{AP}  \\  \\ 
 \frac{60}{TF} = \frac{25}{40}  \\  \\ 
60* \frac{40}{25}=TF \\  \\ 
TF=96mm

So the measure of TF will be 96mm
7 0
3 years ago
The points (-18,15) and (-20,15) lie on a circle with a radius of 1. Find the coordinates of the center of the circle.
FromTheMoon [43]
.hello :
an equation of the circle <span>Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : r = 1
</span><span>The points (-18,15) and (-20,15) lie on a circle with a radius of 1:
</span>(-18-a)²+(15-b)² = 1 ....(1)
(-20-a)² +(15-b)² = 1 ....(2)
solve this system :
(1) -(2) : (-18-a)² - (-20-a)² =0
(-18-a)² =(-20-a)² =0
( -18-a = -20-a) or (-18-a = - (-20-a))
1 )  ( -18-a = -20-a) no solution confused : -18=-20
2 ) -18-a =20+a
      -2a =38
      a = -19 
subst in (1) :(-18+19)²+(15-b)² =1
(15-b)² = 0.... 15-b = 0     .... b = 15
the center is :w(-19,15)
  
6 0
3 years ago
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