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3 years ago

What is 3 tenths more than 8.154 ? What is 2 and 2 tenths more than 1.425? Explain please !

2 answers:

6 0

8.454 is 3 tenths more than 8.154
3.625 is 2 and 2 tenths more than 1.425

Place values after the decimal point are tenths, hundredths, thousandths, ten thousandths...so on.

So 3 tenths looks like this 0.30 ⇒ 3 is in the tenths place. When you say 3 tenths more, it is a clue that the operation to be done is addition. thus,

8.154
+ 0.30
 8.454 * in addition or subtraction, the decimal points must be aligned to avoid confusion.

2 and 2 tenths is like this 2.20 ⇒ 1st 2 is in the ones or units place and the 2nd 2 is in the tenths place. Again it states more than so addition must be done.

1.425
+ 2.20
3.625

lianna [129]3 years ago

6 0

Answer:

8.154

+ 0.30

8.454 * in addition or subtraction, the decimal points must be aligned to avoid confusion.

Step-by-step explanation:

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Which point is an x-intercept of the quadratic function f(x)=(x-4)(x+2)

Mademuasel [1]

Answer:

x = - 2 or x = 4

Step-by-step explanation:

To find the x- intercepts let f(x) = 0, that is

(x - 4)(x + 2) = 0

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x + 2 = 0 ⇒ x = - 2

The x- intercepts are at x = - 2, x = 4

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Slope = 5, passing through (-2,5)

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3 years ago

4t+3c=$81.00 10t+3c=$135.00

muminat

$\left \{ {{4t+3c=81.00\:(I)} \atop {10t+3c=135.00\:(II)}} \right.$
Simplify the first equation by (-1)
 $\left \{ {{4t+3c=81.00\:*(-1)} \atop {10t+3c=135.00\:\:\:\:\:}} \right.$
Once simplified, cancel the opposing terms.
 $\left \{ {{-4t-\diagup\!\!\!\!3c=-81.00} \atop {10t+\diagup\!\!\!\!3c=135.00}} \right.$
Now find the value of "t".
$\left \{ {{-4t=-81.00} \atop {10t=135.00}} \right.$
-------------------------------
$6t = 54.00$
$t = \frac{54.00}{6}$
$\boxed{\boxed{t = 9.00}}\end{array}}\qquad\quad\checkmark$

Now find the value of "c", replace the found value of "t" in the first equation:
$4t+3c=81.00\:(I)$
$4*9+3c=81.00$
$36 + 3c = 81.00$
$3c = 81.00 - 36$
$3c = 45.00$
$c = \frac{45.00}{3}$
$\boxed{\boxed{c = 15.00}}\end{array}}\qquad\quad\checkmark$

Answer:
The values of "t" and "c" satisfying the linear system are successively: $ 9.00 and $ 15.00

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Solve: − <− + 7( − 2) (show your work)

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hope it helps.

<h2>stay safe healthy and happy...</h2>

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3 years ago

Ken went to the store for his mother. He spent $2.37 on groceries. In addition, his mother said he could spend $0.35 on candy. W

Sladkaya [172]

Ken spent $2.37 on groceries and $0.35 on candy, and paid for them with a 5 dollar bill.

To find how much money Ken spent, we add up how much he spent on groceries and candy

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Since he paid with a 5 dollar bill, we need to subtract it from how much he spent to find the change

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Ken got $2.28 in change.

To fill the boxes, it would be

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3 years ago

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