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2 years ago

7

Factorise fully the expression 2d^2-7d

2 answers:

guajiro [1.7K]2 years ago

8 0

Answer:

d(2d-7)

Step-by-step explanation:

2d^2 -7d

take common

=d(2d-7)

DerKrebs [107]2 years ago

8 0

<h2><u> </u><u>Answer</u> :</h2>

$\large \boxed{ \rightarrow d(2d - 7)}$

<h2><u>Solution</u> :</h2>

$\rightarrow2d {}^{2} - 7d$

$\rightarrow d(2d - 7)$

$\mathfrak{hope \:it \: helps \: you.....}$

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2 years ago

2 (a - 5) - 5 = 3<br> Marking brainliest

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1 year ago

Read 2 more answers

Determine if the expression -8c-9c^4d^2−8c−9c

Leto [7]

Answer:

$-8c-9c^4d^2-8c-9c$ is a polynomial of type binomial and has a degree 6.

Step-by-step explanation:

Given the polynomial expression

$-8c-9c^4d^2-8c-9c$

Group like terms

$=-9c^4d^2-8c-8c-9c$

Add similar elements: -8c-8c-9c=-25c

$=-9c^4d^2-25c$

Thus, the polynomial is in two variables and contains two, unlike terms. Therefore, it is a 'binomial' with two, unlike terms.

Each term has a degree equal to the sum of the exponents on the variables.

The degree of the polynomial is the greatest of those.

25c has a degree 1

$-9c^4d^2$ has a degree 6. (adding the exponents of two variables 'c' and 'd').

Thus,

$-8c-9c^4d^2-8c-9c$ is a polynomial of type binomial and has a degree 6.

4 0

2 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

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2 years ago

Five hundred students were asked whether they prefer apple juice or orange juice. The table shown displays the results.

Stells [14]

Answer:

240 more girls

Step-by-step explanation:

210 + 160 = 370

100 + 30 = 130

370 - 130 = 240

5 0

2 years ago