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3 years ago

What do I need to know to ace my test on basic constructions for geometry

Mathematics

2 answers:

ASHA 777 [7]3 years ago

7 0

Answer:

Its important to ask your teacher this alot of tests are different. But just study the general idea of what you've learned so far.

step-by-step explanation:

Brilliant_brown [7]3 years ago

5 0

Answer:

perdón por no ayudar

Step-by-step explanation:

mucho texto

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Someone helppp!!!!!!

Yakvenalex [24]

Mother correct answer is -3,5

8 0

3 years ago

If a and b are two angles in standard position in Quadrant I, find cos(a+b) for the given function values. sin a=15/17and cos b=

tensa zangetsu [6.8K]

The value of $cos(a+b)$ for the angles $a$ and $b$ in standard position in the first quadrant is $-\frac{36}{85}$

We need to find the value of $cos(a+b)$ . To proceed, we need to use the compound angle formula

<h3>Cosine of a sum of two angles</h3>

The cosine of the sum of two angles $a$ and $b$ is given below

$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)$

We are given

$sin(a)=\dfrac{15}{17}\\\\cos(b)=\dfrac{3}{5}$

We need to find $sin(b)$ and $cos(a)$ , using the identity

$sin^2(\theta)+cos^2(\theta)=1$

To find $sin(b)$ , note that

$sin^2(b)+cos^2(b)=1\\\\\implies sin(b)=\sqrt{1-cos^2(b)}$

substituting $\frac{3}{5}$ for $cos(b)$ in the identity, we get

$sin(b)=\sqrt{1-cos^2(b)}\\\\=\sqrt{1-\left(\dfrac{3}{5}\right)^2}=\dfrac{4}{5}$

To find $cos(a)$ , note that

$sin^2(a)+cos^2(a)=1\\\\\implies cos(a)=\sqrt{1-sin^2(a)}$

substituting $\frac{15}{17}$ for $sin(a)$ in the identity, we get

$cos(a)=\sqrt{1-sin^2(a)}\\\\=\sqrt{1-\left(\dfrac{15}{17}\right)^2}=\dfrac{8}{17}$

<h3>Find the value of cos(a+b)</h3>

We can now make use of the formula

$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)$

to find $cos(a+b)$ .

$cos(a+b)=cos(a)cos(b)-sin(a)sin(b)\\\\=\dfrac{8}{17}\cdot\dfrac{3}{5}-\dfrac{15}{17}\cdot\dfrac{4}{5}=-\dfrac{36}{85}$

Learn more about sine and cosine of compound angles here brainly.com/question/24305408

8 0

2 years ago

To show that triangle RPQ=triangle PSR by SSS, what must be the value of x?

VMariaS [17]

If RQ and SP are congruent, then 2x+3=4x-7.
3=2x-7
10=2x
x=5

7 0

3 years ago

Find the equation of the exponential function represented by the table below,

jok3333 [9.3K]

Answer:

Graph the exponential function.

$y=-3(8)^{x}$

Step-by-step explanation:

to make a sketch of this graph. We're gonna make a table of values. I think that's probably our best route. So we'll do a couple negative values, but I'm gonna actually start at 08 to 0. Power zero. And I'm sorry. 80 parts one and one times negative. Three is negative. Three eight to the first. Power is eight and eight times negative. Three is negative. 24 8 X squared is 64 64 times negative. Three is on negative. 192. Okay, I think that's plenty. E to the negative. First power is 18 and 1/8 times negative. Three is negative. 3/8 and eight to the negative. To power is 1 64th times negative. Three is negative. 3 60 force. Okay, I think we can see where that's going. Is getting really close to zero. So as faras my graph here, I'm gonna focus on the fourth quadrant, I think. All right. So we got our X and y axis here. We're starting at 01 and to and we'll also do negative one. And negative two aren't horizontally, vertically. I do. I want to scale this whole the way to 1 92 I guess I will. Um, so whatever it is scaled by, maybe twenties. Yeah, let's do that. 20 40 60 8120 40 60 8200. So there's negative. 200? Um, negative. 1 80 Negative 1 60? Nope. That's not right. Because I scaled by twenties didn't. So this is actually negative. 1 60 This one's negative. 1 20 This one's negative. 80. And this is negative. 40. There we go. All right now a plot. These points to negative 1 92 is practically to 200 one. Negative. 24 is all the way over here. Zero negative three is practically on the X axis The way I have this, and same with those fractional values. They're practically on the X axis. So let's start almost parallel to the X axis because it's never actually touch step than its we don't ever. Slowly and then it starts going down rapidly, decreasing in value to the point where it's almost vertical, but it never will get vertical, so there's a decent sketch of y equals negative three times eight to the power of acts

4 0

2 years ago

PLZ HELP WILL MAKE BRAINLEIST

Jlenok [28]

(1,2)
The solution is where the lines intersect so you can see they intersect at (1,2)

3 0

3 years ago

Read 2 more answers