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lana66690 [7]
3 years ago
11

the three cubes shown weigh 12 ounces how many pounds would 24 cubes weigh A. 4.5 lb B. 6lb C. 18lb D. 72lb

Mathematics
1 answer:
ANEK [815]3 years ago
7 0
The 24 cubes would weigh exactly 6 pounds.
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Suppose that 1/2 of all cars sold at a Nissan dealer in a given year are Altimas, 1/3 are Maximas, and the rest are Sentras. Sup
IRINA_888 [86]

Answer:

(1) Not conditional, 5/8

(2) Not conditional, 1/12

(3) Conditional, 1/18

Step-by-step explanation:

Fraction of cars sold

Altima = 1/2

Maxima = 1/3

Sentra = 1 - (1/2 + 1/3) = 1 - 5/6 = (6 - 5)/6 = 1/6

Fraction of cars sold with moon roof

Altima = 3/4 × 1/2 = 3/8

Maxima = 1/2 × 1/3 = 1/6

Sentra = 1/2 × 1/6 = 1/12

(1) Probability (a randomly selected car has a moon roof) = 3/8 + 1/6 + 1/12 = (9+4+2)/24 = 15/24 = 5/8

(2) Probability (a randomly selected car has a moon roof given it is Sentra) = 1/12

(3) Probability (a randomly selected car is a Maxima if it has a moon roof) = 1/3 × 1/6 = 1/18

A conditional probability uses if (as a condition) in making statements or asking questions

An unconditional probability makes statement or ask question without the use of condition (if)

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3 years ago
3÷3912.00 carry to the hundreth
irga5000 [103]
7.67 is your answer. hope this helps, let me know if you need more help
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Find the flow rate through a tube of radius 6 cm, assuming that the velocity of fluid particles at a distance r cm from the cent
vaieri [72.5K]

Answer:

791.68 cm/s

Step-by-step explanation:

The volume flow rate can be interpreted as the integral of fluid velocity over area

\dot{V} = \int\limits^6_0 {v(r) 2\pi r} \, dr\\\dot{V} = 2\pi\int\limits^6_0 {(25-r^2)r} \, dr\\\dot{V} = 2\pi\int\limits^6_0 {25r-r^3} \, dr\\\\\dot{V} = 2\pi[12.5r^2 - r^4/4]_0^6\\\dot{V} = 2\pi(12.5*6^2 - 6^4/4 - 12.5*0 - 0)\\\dot{V} = 2\pi*126 = 791.68 cm/s

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4 years ago
2x^2-20x+100 quadratic formula
ArbitrLikvidat [17]

Answer:10

Step-by-step explanation:

7 0
3 years ago
Find the volume of the following solid. The solid between the cylinder ​f(x,y)equals=e Superscript negative xe−x and the region
PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy

Now evaluate,

\int_{0}^{ln(6)}e^{-x}dx

which evaluates to,  5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

\int_{-6}^{6}\frac{5}{6}dy = 10

So,

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10

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3 years ago
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