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max2010maxim [7]

3 years ago

5

Can someone please help me?

1 answer:

Reika [66]3 years ago

8 0

The answer is -2 because the the next one is -3

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Someone please help me with this one question

professor190 [17]

Count the length of each side then divide it by 2, then draw those sides, and you will have the 1/8 in.:4ft scale
The length of the actual room, assuming each square is 1/4 in. long, is 40ft and the width is 24ft
And then the area would be 40 * 24 = 960 sqft.

6 0

3 years ago

Which number can be removed from the following list of data so that the median will remain the same?

Anestetic [448]

B) you can remove 55 and it'll stay the same

8 0

3 years ago

Read 2 more answers

Plz help<br> i will give brainlest

worty [1.4K]

Answer:

Option C

Step-by-step explanation:

${ (\frac{ {x}^{4} }{ {7}^{ - 8} } ) }^{ - 7}$

$= \frac{ {x}^{4( - 7)} }{ {7}^{( - 8)( - 7)} }$

$= \frac{ {x}^{ - 28} }{ {7}^{56} }$

${x}^{ - 28} \times {7}^{ - 56}$

3 0

3 years ago

If I could get help………

charle [14.2K]

Answer:

$x1 = 3 \\ y1 = 10 \\ x2 = 5 \\ y2 = 12 \\ y - y1 = \frac{y2 - y1}{x2 - x1} (x - x1) \\ y - 10 = \frac{2}{2} (x - 5) \\ y = x - 5 + 10 = x + 5$

enjoy it

8 0

3 years ago

When throwing fair dice, all six faces of each die are equally likely. there are thirty-six total possible outcomes (any of the

Marysya12 [62]

Answer:

Probability of sum of pips on two faces is at least 9 = $\frac{5}{18}$

Step-by-step explanation:

Experiment: Throwing two fair dice.

Total no of Outcome = $6^2$ = 36

Sample space (list of outcome) is attached.

Let E be the event that sum of pips on two faces is at least 9.

$Probability \:(\,Event \:E\,)\: =\;\frac{No.\: of\: favorable\: outcome\:of\: Event\: E}{Total\: No.\: of \:Outcome}$

Favorable outcome are where sum is 9 , 10 , 11 and 12.

From Sample space, No. of Favorable outcome = 10

∴ $Prob\: (\: E\: ) = \frac{10}{36}$

$Prob\: (\: E\: ) = \frac{5}{18}$

6 0

3 years ago