I attached the work/steps for my answer.
Answer:
(3,1)
Step-by-step explanation:
Answer:
The problem can't be factor
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
perpecndicular means they intersect in right angle which is 90°, no matter how long lines are.
Answer:

Step-by-step explanation:
Coordinates of Point b
b lies on the circle whose equation is 

Comparing with the general form a circle with center at the origin: 
The radius of the circle =17 which is the length of the hypotenuse of the terminal ray through point b.
For an angle drawn in standard position through point b,
x=-8 which is negative
y=15 which is positive
Therefore, the angle is in Quadrant II.
