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Ad libitum [116K]
3 years ago
12

Given: Angle 0 is in quadrant III and sin0 = -sqrt(6)/4 Prove: cos0 = -sqrt(10)/4

Mathematics
1 answer:
zavuch27 [327]3 years ago
8 0

Answer:

Below.

Step-by-step explanation:

The cosine is also negative in Quadrant III.

sin^2 O + cos^2 O = 1

cos^2 O = 1 - sin^2 O

= 1 - (-sqrt(6)/4)^2

= 1 -  (6/16)

=  16/16 - 6 /16

= 10/16

So cos O = -sqrt(10/16)

= -sqrt(10)/4.

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