Answer:
Step-by-step explanation:
This problem can be solved by using the expression for the Volume of a solid with the washer method
![V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint%20%5Climit_a%5Eb%5BR%28x%29%5E2-r%28x%29%5E2%5Ddx)
where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).
Before we have to compute the limits of the integral. We can do that by taking f=g, that is
there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)
x1=0.14
x2=8.21
and because the revolution is around y=-5 we have
and by replacing in the integral we have
![V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5Cint%20%5Climit_%7Bx1%7D%5E%7Bx2%7D%5B%28lnx%2B5%29%5E2-%28%5Cfrac%7B1%7D%7B2%7Dx%2B3%29%5E2%5Ddx%5C%5C)
![V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]](https://tex.z-dn.net/?f=V%3D%5Cpi%20%5B28x%2B%5Cfrac%7B1%7D%7Bx%7D%2Bxln%5E2x-12xlnx-6lnx%5D)
and by evaluating in the limits we have
Hope this helps
regards
Answer:
Step-by-step explanation:
i honesty dont know if so i would help
The answer would be -21.6
Answer:
interest earned= 292.878
the future value of an annuity= 892.878
Step-by-step explanation:
Given Data:
Interest rate= 5%
time,t = 8 years
Quarterly payment, P= 600
n= 4 as quarterly
At the end of 8 years, final investment A= ?
As per the interest formula
A= P(1+r/n)^nt
= 600(1+0.05/4)^32
= 892.878
Interest earned = A-P
= 892.878-600
= 292.878 !
Answer:
21.33 to nearest hundredth
Step-by-step explanation:
Inverse Variation is y = k / x where k is a constant.
Plug in the given values to find k:-
16 = k/4
k = 4*16 = 64 so the equation of variation is y = 64/x.
So when x = 3, y = 64/3 = = 21.33 to nearest hundredth.
