Log4 x + log4(x-12)= 3 Help??

Mathematics

1 answer:

otez555 [7]3 years ago

3 0

Step-by-step explanation:

log4(x) + log4(x - 12) = 3

log4[x(x - 12)] = log4(4³)

=> x(x - 12) = 4³

=> x² - 12x = 64

=> x² - 12x - 64 = 0

=> (x - 16)(x + 4) = 0

=> x = 16 or x = -4 (rejected as log of a negative number is undefined)

Hence x = 16.

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Answer:

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