The answer is -6
(9-15)=-6
(-8+2)=-6
(24-30)=-6
-(-6)+(-6)-(-6)= -6
The answer to your problem is A 1/3, is the possibility for a passenger who arrives at noon.
Well 2 years is 24 months. 24 divided by 4 is 6. 200 multiplied by 6 would equal 1200.
The total population of crickets after two years would be 1200.
1/5 (150x - 80y + 50 - 50x - 25y + 20) = 20x - 21y + 14
what I did is combined the like terms and multiplied each term within the parenthesis by .2
A=3,500×(1+0.0485÷4)^(4×11)
A=5,947.99
6000=3500(1+0.0485/4)^4t
Solve for t to know the time needed to reach 6000
Time=11.2
So the time needed is 11 years and 2 months
