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3 years ago

Help please solving this multiplication not sure.

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

6 0

4 x 5 = 20 , 1 x 5 = 5.
20 chew bones and 5 dog toys.

Rashid [163]3 years ago

4 0

Chew bones
if he gives 4 per month then in 5 months you would solve 4 x 5 =

Dog toy
if he gives 1 per month then in 5 months you would solve 1 x 5 =

let me know what you got for the answer

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Triangle ABC has vertices at A(2, 2), B(4,7), and C(6,2). Classify the triangle according to the side lengths.

zmey [24]

Answer:

Isosceles triangle

Step-by-step explanation:

Length AB

√(4 - 2)² + (7 - 2)²

√2² + 5²

√4 + 25

√29

Length AC

6 - 2 = 4

Length BC

√(6 - 4)² + (2 - 7)²

√2² + (-5)²

√4 + 25

√29

Length AB and BC is the same.

Length AC is the longest side.

Therefore, it is an isosceles triangle.

4 0

3 years ago

There were 100 questions on a math test. If Jamal got 4 times as many right as he got wrong, what was Jamals score?

IgorLugansk [536]

Jamal's score is 80

<u>Explanation:</u>

Given:

Number of questions = 100

Let w be the number of wrong answers

Let r be the number of right answers

According to question,

r = 4w

r + w = 100

Solving both the equations we get:

4w + w = 100

5w = 100

w = 20

If w = 20 then r = 4 X 20 = 80

Therefore, Jamal's score is 80

7 0

3 years ago

URGENT!!!!!!!!!!!!!!!!

Kruka [31]

Answer:

0.5 over 1

Step-by-step explanation:

look at how much it goes down

8 0

2 years ago

What Is 7 Rounded To The Nearest Tenth?

AnnyKZ [126]

I think that it is 7.0

5 0

3 years ago

Geometric sequences HELP ASAP!

Pani-rosa [81]

Given:

The table for a geometric sequence.

To find:

The formula for the given sequence and the 10th term of the sequence.

Solution:

In the given geometric sequence, the first term is 1120 and the common ratio is:

$r=\dfrac{a_2}{a_1}$

$r=\dfrac{560}{1120}$

$r=0.5$

The nth term of a geometric sequence is:

$a_n=ar^{n-1}$

Where a is the first term and r is the common ratio.

Putting $a=1120, r=0.5$ , we get

$a_n=1120(0.5)^{n-1}$

Therefore, the required formula for the given sequence is $a_n=1120(0.5)^{n-1}$ .

We need to find the 10th term of the given sequence. So, substituting $n=10$ in the above formula.

$a_{10}=1120(0.5)^{10-1}$

$a_{10}=1120(0.5)^{9}$

$a_{10}=1120(0.001953125)$

$a_{10}=2.1875$

Therefore, the 10th term of the given sequence is 2.1875.

6 0

2 years ago