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klasskru [66]
3 years ago
6

Today, scientists agree that good research is ethical in nature and is guided by basic respect for human dignity and safety. How

ever, as you read in the Tuskegee Syphilis Study, this was not the case. Discuss any THREE (3) the ethical violations in the study
Computers and Technology
1 answer:
Ksivusya [100]3 years ago
4 0

Answer:

Ethical violations in the Tuskegee Syphilis Study

1)  Discrimination. Syphilis was recognized as a disease with a major impact on the afro-descendant and in poor conditions population. The studied population was not treated fairly, they were selected from a vulnerable group. Against the bioethical principles of justice.

2) The ethical principle of beneficence was violated since the participants did not have a real benefit from their participation and in the case of the sick people, they had no option to be treated (in 1947 penicillin was already used as a treatment).

Due to the ignorance of the study, the general population was affected by the transmission of the infectious disease.

3) There was no informed consent against the autonomy principle of clinical Ethic. People were studied for about 40 years (1932 - 1972) with no information about it.

Explanation:

It was a study conducted by the Public Health Service in the city of Tuskegee (Alabama). The objective was the study of the natural progression of syphilis.

The controversies regarding this study were related to the fact that it was conducted in an African American and literate population that was not informed and did not have access to treatment.

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Consider a company that needs to sort an array of structures of type Customer by balance, with the largest balance first. Here i
8090 [49]

Answer:

#include <iostream>

#include <string>

#include <cstring>

#include <cstdlib>

using namespace std;

struct Person

{

string name;

int age;

};

int main()

{

struct Person data[10];

struct Person *pData[10],*temp;

string names[] = {"a","b","c","g","z","l","p","q","r","w"};

int num[] = {4,6,34,8,13,90,33,22,18,23};

for(int i=0;i<9;i++)

{

data[i].name = names[i];

data[i].age = num[i];

pData[i] = &data[i];

}

for(int i=0;i<9;i++)

{

for(int j=i+1;j<9;j++)

{

if(pData[i]->name.compare(pData[j]->name)>0)

{

temp = pData[i];

pData[i] = pData[j];

pData[j] = temp;

}

}

}

for(int i=0;i<9;i++)

{

cout<<pData[i]->name<<" "<<pData[i]->age<<endl;

}

}

Explanation:

The line #include <iostream> initializes the program.

This program created an array of only 10 structures, Customer data. Also defined an auxiliary array Customer *pData.

The program uses these parameters to sorts the array of pointers so that when you go through pData in increasing order of index k, the entries pData[k] point to Customer objects in decreasing order by balance, meaning that pdata[0] now points to the customer with the highest balance, and pData[9] points to the customer with the smallest balance.

4 0
3 years ago
What is not true of efs
Lemur [1.5K]

Answer:

EFS cannot store files encrypted.

Explanation:

EFS) is a feature introduced in version 3.0 of NTFS that provides filesystem-level encryption. EFS is useful for mobile computer users, whose computer are subject to physical theft, and for storing highly sensitive data. Encryption itself is the method where the information is converted into secret code that hides the information's true meaning. (EFS) is used to encrypt files and folders. EFS is easy to use, with nothing more than a check box in a file’s properties. It is not fully supported on Windows 7 Starter, Windows 7 Home Basic, and Windows 7 Home Premium!

3 0
3 years ago
Two routers, R1 and R2, connect using an Ethernet over MPLS service The service provides point-to-point service between these tw
liberstina [14]

Answer: b) R1 will connect to a physical Ethernet link, with the other end of the cable connected to a device at the WAN service provider point of presence.

.d) R1 will forward data link frames to R2 using an Ethernet header/trailer.

Explanation:

Here we have to understand what is MLPS. MLPS is a protocol which identifies the shortest route for the transfer of messages between routers instead of the longest route.

Here we are given a WAN which is a wide area network. Using layer 2 Ethernet service the frames are transmitted across the routers within the WAN.

Option A is incorrect as as connecting the other end of the cable to the R2 would reduce the functionality of the WAN.  Option C is incorrect as HDLC header trailer has no effect.

Option B and D are correct as Ethernet header/ trailer has the same size every frame and to maintain the functionality of the WAN one end must be connected to point of presence(PoP).  

5 0
3 years ago
A pointing device used mainly for computer games is known as
kolbaska11 [484]

Answer: Joystick is the only one that makes sense, a stylus and digitizer are both used on drawing tablets, not computer games.

5 0
2 years ago
Endnotes are indicated by
V125BC [204]

Answer:

The answer is D because u have the uppercase letter bold

4 0
3 years ago
Read 2 more answers
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