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Lelechka [254]
3 years ago
15

In an executing process, the program counter points __________.

Computers and Technology
1 answer:
ahrayia [7]3 years ago
6 0

Answer:

To the next instruction to be executed and is incremented after each instruction has been executed.

Explanation:

Given that Program counter is a form of record or directory in a computer processor that has the location of the instruction that is currently being executed.

This it does in such a way that, following the execution of each instruction, the program counter increases the number of instructions it stored and immediately points to the subsequent instruction that follows.

Hence, in an executing process, the program counterpoints "To the next instruction to be executed and is incremented after each instruction has been executed."

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What are the two access modes that are used when opening a file for input and output when pickling?
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The two access modes that are used when opening a file for input and output when pickling are rb and wb.

<h3>What is pickling?</h3>

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2 years ago
In ________- key encryption, two keys, known as a key pair, are created, where one key is used for coding and the other key for
Pavel [41]
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g Create a package named lab7 (no spaces, ALL in lowercase) where you will place your lab files. Write a class FilterWith with a
sweet [91]

Answer:

See explaination

Explanation:

import java.util.ArrayList;

import java.util.Scanner;

public class ListFilter

{

public static void filterRange(ArrayList<Integer> list,int min, int max)

{

ArrayList<Integer> listNew=new ArrayList<Integer>();

for(int i=0;i<list.size();i++)

{

if(list.get(i)>=min && list.get(i)<=max) //Checking if element is between min and max

{

listNew.add(list.get(i));

}

}

list.removeAll(listNew); //removing all elements from list.

}

public static void main(String[] args)

{

ArrayList<Integer> list=new ArrayList<Integer>();

list.add(4);

list.add(7);

list.add(9);

list.add(2);

list.add(7);

list.add(7);

list.add(5);

list.add(3);

list.add(5);

list.add(1);

list.add(7);

list.add(8);

list.add(6);

list.add(7);

Scanner sc=new Scanner(System.in);

System.out.println("Enter min : ");

int min=sc.nextInt();

System.out.println("Enter Max : ");

int max= sc.nextInt();

filterRange(list, min, max);

//Displaying new List

for(int i=0;i<list.size();i++)

{

System.out.print(list.get(i)+" ");

}

}

}

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3 years ago
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