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Ivenika [448]
3 years ago
9

Frankie buys six and twelve fifteenths pounds of cherries and four and four sixths pounds of grapes. How many pounds of fruit di

d she buy in total?
ten and forty two ninetieths pounds
ten and sixteen twenty firsts pounds
eleven and forty two ninetieths pounds
eleven and sixteen twenty firsts pounds
Mathematics
2 answers:
Bas_tet [7]3 years ago
7 0

Answer: I think it’s the 3rd one

Step-by-step explanation:

Marina86 [1]3 years ago
5 0

Answer:

eleven and sixteen twenty firsts pounds

Step-by-step explanation:

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Benjamin has enough icing to cover a 12-square-foot cake.
bazaltina [42]

Answer:

The area of each of the 2 equal-sized cakes shall behalf of 12 ft²: 12 ft² / 2 = 6 ft²

Step-by-step explanation:

5 0
3 years ago
Which statement proves that quadrilateral JKLM is a kite?
sesenic [268]
A quadrilateral is a kite if the diagonals are:

i) perpendicular
ii) bisect each other
iii) not equal ( together with conditions i and ii this would make the quadrilateral a square)


Another definition of the kite is :

a quadrilateral with 2 pairs of equal adjacent sides.


Let's check the choices one by one:

A. <span>∠M is a right angle and MK bisects ∠LMJ.

according to these, ML and MJ may well be not equal...


</span><span>B. LM = JM = 3 and JK = LK = √17.
</span>
this makes the quadrilateral a kite.


<span>C. MK intersects LJ at its midpoint
</span>
if they are not perpendicular, the quadrilateral is not a kite.


<span>D. The slope of MK is –1 and the slope of LJ is 1.

this only means that MK and LJ are perpendicular, but not whether they bisect each other,


Answer: only B</span>
9 0
3 years ago
Read 2 more answers
What is the product?
AleksandrR [38]

Multiply 6 by each number in the matrix:

24, -12, 6

42, 18, 0

The 3rd answer is the correct one.

3 0
3 years ago
Mrs. Montgomery earns a 6.5% commission on her total sales. Last month, she had sales of $55,780.
jok3333 [9.3K]

Answer:

Commission: $3625.70

Total (sales + commission): $59405.70

Step-by-step explanation:

6.5% of 55780 = 0.065 × 55780 = 3625.7

55780 increase 6.5% =

55780 × (1 + 6.5%) = 55780 × (1 + 0.065) = 59405.7

7 0
3 years ago
To evaluate the effect of a treatment, a sample is obtained from a population, with a mean of u = 30, and the treatment is admin
Murrr4er [49]

Answer:

a) t=\frac{31.3-30}{\frac{3}{\sqrt{16}}}=1.733  

p_v =2*P(t_{15}>1.733)=0.104  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the we don't have a significant effect for the new treatment at 5% of significance.  

b) t=\frac{31.3-30}{\frac{3}{\sqrt{36}}}=2.6  

p_v =2*P(t_{15}>2.6)=0.0201  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the we have a significant effect for the new treatment at 5% of significance.  

c) When we increase the sample size we increse the probability of rejection of the null hypothesis since the z score tend to increase when the sample size increase.

Step-by-step explanation:

Data given and notation  

Part a: If the sample consists of n=16 individuals, are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with alpha = 0.05.

\bar X=31.3 represent the sample mean  

s=3 represent the sample standard deviation  

n=16 sample size  

\mu_o =30 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 30, the system of hypothesis are :  

Null hypothesis:\mu = 30  

Alternative hypothesis:\mu \neq 30  

Since we don't know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{31.3-30}{\frac{3}{\sqrt{16}}}=1.733  

P-value  

First w eneed to find the degrees of freedom given by:

df=n-1=16-1 =15

Since is a two-sided test the p value would given by:  

p_v =2*P(t_{15}>1.733)=0.104  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the we don't have a significant effect for the new treatment at 5% of significance.  

Part b: If the sample consists of n=36 individuals, are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with alpha = 0.05.

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{31.3-30}{\frac{3}{\sqrt{36}}}=2.6  

P-value  

First w eneed to find the degrees of freedom given by:

df=n-1=16-1 =15

Since is a two-sided test the p value would given by:  

p_v =2*P(t_{15}>2.6)=0.0201  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the we have a significant effect for the new treatment at 5% of significance.  

Part c; Comparing your answer for parts a and b, how does the size of the sample influence the outcome of a hypothesis test

When we increase the sample size we increse the probability of rejection of the null hypothesis since the z score tend to increase when the sample size increase.

5 0
3 years ago
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