Answer:
The price of the cell phone without the coupon= $500
Step-by-step explanation:
Step 1: Express discounted amount
The discounted amount can be expressed as a function of the original cost of the phone as follows;
D=r×A
where;
D=discounted amount
r=coupon rate
A=original price of the cell phone before the coupon
In our case;
r=45%=45/100=0.45
A=a
replacing;
Discounted amount=(0.45×a)=0.45 a
Step 2: Amount she pays up
Amount she pays=Original cost of cell phone-discounted amount
where;
Amount she pays= $275
original cost of cell phone=a
discounted amount=0.45 a
replacing;
$275=a-0.45 a
0.55 a=275
a=275/0.55
a=500
The price of the cell phone without the coupon= $500
Answer:
<em>64 degrees</em>
Step-by-step explanation:
When you have the SRQ angle, you can easily solve for PQR. Luckily, we're given that QRP and PRS are 32 and 84, respectively. Adding this together gives you 116. 116*2 = 232 and 360-232 = 128, and 128/2 = 64.
<em>Please Mark Brainliest if this helps!</em>
<span>1. a sine curve with amplitude 2, and period 4pi radians
</span>
the general equation of the sine curve ⇒⇒ y = a sin (nθ)
where: a is the amplitude and n = 2π/perid
∵ <span>amplitude 2, and period 4pi radians
</span>
∴ y = 2 sin (θ/2)
The correct answer is option D. y = 2 sin (θ/2)
===========================================
<span>2.The period and amplitude of the function ⇒⇒ y = 5 cos 2θ
</span>
<span>comparing with y = a cos nθ
</span>
where : a is the amplitude and n = 2π/period
<span>amplitude = 5 , period = 2π/n = 2π/2 = π
</span>
The correct answer is option B. Period: pi radians: Amplitude:5
============================================================
3. tan (2π/3) = tan 120° = -√3
120° lie in the second quadrant and its reference angle = 180° - 120° = 60°
tan function in the second quadrant is negative
∴ tan 120° = - tan 60 = -√3
The correct answer is C. -sqrt3
=====================================================
4. <span>Tan 5π/6 = tan 150° = -(√3)/3
</span>
150° lies in the second quadrant and its reference angle = 180° - 150° = 30°
tan function in the second quadrant is negative
∴ tan 150° = - tan 30 = -(√3)/3
The correct answer is <span>B.-sqrt3/3</span>
Answer:
1. C) 3
2. D) -1
3. D) 7^2 - 8*2 - 16
4. B) 75
5. B) 6^2 + (2 - 8)*sqrt(81)
Step-by-step explanation:
1. (10 - (6-4)^2)/2
= (10 - 2^2)/2
= (10 - 4)/2
= 6/2
= 3
2. PEMDAS states that Multiplication is before Subtraction
8 - (5^2-7)/2
= 8 - (25-7)/2
= 8 - 18/2
= 8 - 9
= -1
3. D) 7^2 - (8*2) - 16
= 49 - 16 - 16
= 49 - 32
= 17
4. 3(2 + 3)^2
= 3(5)^2
= 3(25)
= 75
5. 6^2 + (2 - 8)*sqrt(81)
= 36 + (-6*9)
= 36 - 54
= -18
