Answer:
○ A. No, x = -16 is not a zero of the polynomial.
The quotient is x² - 2x + 83, and the remainder is -1274.
Step-by-step explanation:
This is not a zero. When set to equal zero, you get these roots: -2, -3, -9. Now, about the the Remainder Theorem, I have not been taught this, but just by looking at it, I come across this as the remainder.
I am joyous to assist you anytime.
* I cross my fingers for it to be correct!
The pattern on the table is x increases:
- The sine of x increases
- The cosine of x increases
- The function sin²(x) + cos²(x) remains constant
<h3>How to describe the pattern?</h3>
The functions on the table of values are:
sin(x), cos(x) and sin²(x) + cos²(x)
To describe the pattern, we simply observe how the values of the function change, as x increases.
As x increases, on the table:
- The sine of x increases
- The cosine of x increases
- The function sin²(x) + cos²(x) remains constant
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#1
avatar+34237
0
Temp in city for weeks 1-4 = Starting temp - (20 deg C / 4 wk) * wk#
Temp in City for weeks 1-4 = starting temp - 5 deg c/wk * wk#
This shows the temperature in the city for weeks 1 2 3 4 given the original temperature of the city and whichever week you want to know from the starting point....week 1 week 2 week 3 week 4 .....
The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma(
)
E(X)=
=
=6 weeks
V(x)=
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X,
,
, False)
P(
)
P(
)
P(
)
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
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