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umka2103 [35]
2 years ago
10

What angle is this??

Mathematics
2 answers:
Juli2301 [7.4K]2 years ago
7 0

Answer:

Acute Triangle

Step-by-step explanation:

Since all of the numbers are below 90 degrees, therefore, it makes it into an acute triangle.

Hope this helps! Stay safe!

Dima020 [189]2 years ago
3 0
The correct answer is B
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(7 x 18 + 45) : 3 x 2 what is it please?​
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The Answer Is 171 : 6

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Is 3:4 and 2:3 eqavalent
mrs_skeptik [129]

Answer:

No.

Step-by-step explanation:

They are not equivalent ratios because they are not multiples or dividends.

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6 0
3 years ago
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These figures are congruent. What is the length of side LM?
sergiy2304 [10]

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5

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4 0
2 years ago
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729 = blank to the third power
Crazy boy [7]
One way is to factor and group and get every 3
729=3 times 3 times 3 times 3 times 3 times 3
so we group the ones that happen 3 times
729=(3*3*3) times (3*3*3)
we know that we can take the cube root of each group and multiply the result
729=( \sqrt[3]{3*3*3})( \sqrt[3]{3*3*3})=(3)(3)=9

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4 0
3 years ago
Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point
Maksim231197 [3]

Answer: (6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0) are the required points.

or  (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]

Taking square on both the sides , we get

(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0

Using quadratic formula : x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}

so, (6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0) are the required points.

since \sqrt{3}=1.732

so, (6+7(1.732),0)\text{ and }(6-7(1.732),0) are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

3 0
3 years ago
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