Question 2

Which element is probably most like carbon

Arte-miy333 [17]

In terms of chemical properties, elements found within the group that contains carbon, would be similar in term of chemical reactivities etc.

5 0

3 years ago

A 3.00-L flask is filled with gaseous ammonia, NH3. The gas pressure measured at 27.0 ∘C is 2.55 atm . Assuming ideal gas behavi

Whitepunk [10]

Answer : The mass of ammonia present in the flask in three significant figures are, 5.28 grams.

Solution :

Using ideal gas equation,

$PV=nRT\\\\PV=\frac{w}{M}\times RT$

where,

n = number of moles of gas

w = mass of ammonia gas = ?

P = pressure of the ammonia gas = 2.55 atm

T = temperature of the ammonia gas = $27^oC=273+27=300K$

M = molar mass of ammonia gas = 17 g/mole

R = gas constant = 0.0821 L.atm/mole.K

V = volume of ammonia gas = 3.00 L

Now put all the given values in the above equation, we get the mass of ammonia gas.

$(2.55atm)\times (3.00L)=\frac{w}{17g/mole}\times (0.0821L.atm/mole.K)\times (300K)$

$w=5.28g$

Therefore, the mass of ammonia present in the flask in three significant figures are, 5.28 grams.

8 0

4 years ago

Calculate the molar mass of ammonium chloride

il63 [147K]

Answer:

53.491 g/mol

Explanation:

Create the chemical compound and find each individual element's molar mass. Lastly, add them up.

3 0

3 years ago

What is the solubility (in g/L) of calcium fluoride at 25°C? The solubility product constant for calcium fluoride is 3.4 × 10–11

PilotLPTM [1.2K]

<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

$CaF_2\rightleftharpoons Ca^{2+}+2F^-$

s 2s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Ca^{2+}][F^-]^2$

We are given:

$K_{sp}=3.4\times 10^{-11}$

Putting values in above equation, we get:

$3.4\times 10^{-11}=(s)\times (2s)^2\\\\3.4\times 10^{-11}=4s^3\\\\s=2.04\times 10^{-4}mol/L$

To calculate the solubility in g/L, we will multiply the calculated solubility with the molar mass of calcium fluoride:

Molar mass of calcium fluoride = 78 g/mol

Multiplying the solubility product, we get:

$s=2.04\times 10^{-4}mol/L\times 78g/mol=159.12\times 10^{-4}g/L=0.015g/L$

Hence, the correct answer is Option b.

3 0

3 years ago

Big question for physicists out there:How can we be sure dark matter actually exists in our universe?

DanielleElmas [232]

Answer:

We can see the bright matter, like stars, but we know some other matter is there(dark matter)because of how it pulls on the bright matter.

Explanation:

6 0

3 years ago