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WINSTONCH [101]
2 years ago
10

Sulfuric acid solid aluminum hydroxide to form liquid water and a solubale salt. What is the balance equation

Chemistry
1 answer:
Hatshy [7]2 years ago
6 0

Balanced chemical equation for the reaction between sulfuric acid & solid aluminum hydroxide to form liquid water and a soluble salt is 3H₂SO₄ + 2Al(OH)₃  Al₂(SO₄)₃ + 6H₂O.

<h3>What is balanced equation?</h3>

Balanced chemical equations are those in which all entities are present in same amount on both sides of the chemical equation.

Balanced chemical reaction for the given compounds will be shown as:

3H₂SO₄ + 2Al(OH)₃  Al₂(SO₄)₃ + 6H₂O

Above chemical equation is the balanced equation as all atoms are present in same amount on the left side as well as on the right side of the reaction.

Hence balanced equation is 3H₂SO₄ + 2Al(OH)₃  Al₂(SO₄)₃ + 6H₂O.

To know more about balanced equation, visit the below link:

brainly.com/question/26227625

#SPJ4

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Gasoline will not dissolve in water because gasoline has more density then the water
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Suppose that H2SO4 was used in the reaction instead of HCl. How many moles of NaOH would neutralize 1 mole of H2SO4?
arlik [135]

Answer: Hence, 2 moles of NaOH would neutralize 1 mole of H_2SO_4

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

One mole of hydrochloric acid neutralizes one mole of sodium hydroxide to give one mole of sodium chloride and one mole of water

When sulfuric acid is used in the place of HCl , 1 mole of sulfuric acid will neutralizes the 2 mole of sodium hydroxide and gives one mole of sodium sulfate and 2 moles of water. As we can see from the reaction:

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

Hence, 2 moles of NaOH would neutralize 1 mole of H_2SO_4

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3 years ago
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Fluorine-18 is a radioactive isotope that decays by positron emission to form oxygen-18 with a half-life of 109.8 min. (A positr
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Answer:

k = 6.31 x 10⁻³ min⁻¹

Explanation:

The equation required to solve this question is:

k = 0693 / t half-life

This equation is derived from the the equation from the radioctive first order reactions:

ln At/A₀ = -kt

where At is the number of isoopes after a time t , and A₀ is the number of of isotopes initially. The half-life is when the number of  isotopes has decayed by a half, so

ln(1/2) = -kt half-life

-0.693 = - k t half-life

t half-life = 109.8 min

⇒ k = 0.693 / t half-life = 0.693 / 109.8 min = 6.31 x 10⁻³ min⁻¹

6 0
3 years ago
Given the elements chlorine, iodine, oxygen, bromine, and fluorine, organize by increasing atomic size (atomic radius). Justify
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3 0
3 years ago
Starting with the stock solution of 6.0 M, how many milliliters of 6.0 M sulfuric acid are needed to make 450 mL of 1.2 M soluti
Lina20 [59]

<u>Answer:</u> The volume of stock solution needed is 90 mL

<u>Explanation:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock sulfuric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted sulfuric acid solution

We are given:

M_1=6.0M\\V_1=?mL\\M_2=1.2M\\V_2=450mL

Putting values in above equation, we get:

6.0\times V_1=1.2\times 450\\\\V_1=\frac{1.2\times 450}{6.0}=90mL

Hence, the volume of stock solution needed is 90 mL

6 0
3 years ago
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