Question

A bag contains 20 slips of paper Individually numbered. If a slip of paper and a letter in the word PENNSYLVANIA is chosen at randomfind each probability.

Answer 1

Answer:

$P(M4\ n\ V) = 2.083\%$

Step-by-step explanation:

Given

Paper = 20 slips

Word: PENNSYLVANIA

Required

Determine P(Multiple of 4 and V)

The sample size of the 20 slips is:

$n(S) = 20$

The outcomes of multiples of 4 is:

$M4= \{4,8,12,16,20\}$

$n(M4) = 5$

So, the probability of multiples of 4 is:

$Pr(M4) = \frac{5}{20}$

$Pr(M4) = \frac{1}{4}$

The sample size of PENNSYLVANIA is:

$n(S) = 12$

The outcome of V is:

$n(V) = 1$

So, the probability of V is:

$P(V) = \frac{1}{12}$

So, the required probability is: P(Multiple of 4 and V)

$P(M4\ n\ V) = P(M4) * P(V)$

$P(M4\ n\ V) = \frac{1}{4} * \frac{1}{12}$

$P(M4\ n\ V) = \frac{1}{48}$

$P(M4\ n\ V) = 0.02083$

Express as percentage

$P(M4\ n\ V) = 0.02083 * 100\%$

$P(M4\ n\ V) = 2.083\%$