Answer:
Interval Notation: (
−
∞
,
3
)
∪
(
3
,
∞
)
Set-Builder Notation: {
x
|
x
≠
3
}
Answer:
The ordered pair that contains the solution to the equation lies in Quadrant I.
The solution to the equation is x=2
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Instantaneous rate of change = S'(r) = 8πr
S'(8) = 8π(8) = 64π
Therefore, the instantaneoud rate of change of the <span>surface area with respect to the radius r at r = 8</span> is 64π