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VladimirAG [237]
3 years ago
13

Going against the current, a boat takes 6 hours to make a 120-mile trip. When the boat travels with the current on the return tr

ip, it takes 5 hours.
What is the rate of the boat in still water?
Mathematics
1 answer:
tankabanditka [31]3 years ago
5 0

Answer:

  22 miles per hour

Step-by-step explanation:

Against the current, the boat's rate of travel is ...

  (120 mi)/(6 h) = 20 mi/h

With the current, the boat's rate of travel is ...

  (120 mi)/(5 h) = 24 mi/h

___

The sum of boat speed (b) and current speed (c) is 24 mph. The difference is 20 mph. This lets us write the equations ...

  b + c = 24

  b - c = 20

Adding these two equations together, we get ...

  2b + 0c = 44

  b = 22 . . . . . . . . divide by 2

The rate of the boat in still water is 22 miles per hour.

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Step-by-step explanation:

1.5 mi = 2 and 1/4 min

In 43 minutes:

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Now you have to multiply 1.5 by 20

1.5 x 20 = 30

In 1 hour (60 minutes):

60 ÷ 2.15 = 27.9

Now you have to multiply 1.5 by 27.9

1.5 x 27.9 = 41.85

Hope this was helpful :)

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Read 2 more answers
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