Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
Answer:
The cost of each cotton candy bag is $4.
Step-by-step explanation:
Consider the provided information.
Let, the vendor has 
dollar at the starting of each day.
Let, the cost of each cotton candy bag is 
.
Now when she sells a total of 12 bags, she has $128.
.....(1)
After she sells a total of 20 bags, she has $160.
....(2)
Subtract equation 1 from equation 2.
Hence, the cost of each cotton candy bag is $4.
Answer:
112
Step-by-step explanation:
So, we know that a triangle's sides must add up to have a sum of 180. If you add up your given lengths and you should get 47, not including x. Then if you look at the left side/the one without a given length and it should be identical to the 21, so you know that side is 21. So now add 21 to 47, you should get 68. Finally, you subtract 68 from 180 like this: 180-68, and it should equal 112. So you're answer is 112.
Answer:
6x
Step-by-step explanation:
3x*3x= 9x - 3x = 6x
