3 years ago

Find GH. Round to the nearest hundredth.

Mathematics

1 answer:

Bond [772]3 years ago

7 0

You need to use the cosine for this and this is how you do it.

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Hoochie [10]

Answer:

Part 1) There are two real solutions

Part 2) There is one real solution

Part 3) There are no real solutions

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

If the radicand is positive

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If the radicand is zero

$(b^{2}-4ac) =0$ ------> There is one real solution

If the radicand is negative

$(b^{2}-4ac)$ ------> There are no real solutions

therefore

Part 1) The radicand is positive

There are two real solutions

Part 2) The radicand is equal to zero

There is one real solution

Part 3) The radicand is negative

There are no real solutions

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<span>The end behavior of a polynomial function is the behavior of the graph of f as
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