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vodomira [7]
3 years ago
13

HELP!! A,b,or C need it asap

Mathematics
2 answers:
alekssr [168]3 years ago
8 0
B.


I need 20 letters
AVprozaik [17]3 years ago
5 0

Answer:

the answer is b

Step-by-step explanation:

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Find the area of this figure! (Don’t give me a big explanation, i have 30 mins to get this ixl to 90, currently at 74)
Evgen [1.6K]

315 m²

<u><em>area of rec + area of rec + area of rec +  area of triangle</em></u>

⇒ length + width + length + width + length + width + 1/2 * base * height

⇒ 19 * 6 + 9 * 9 + 18 * 5 + 1/2 * 12 * 5

⇒ 90 + 30 + 81 + 114

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2 years ago
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Nina’s garden is 4 1/5 meters long and 3/10 meter wide. What is the area of Nina’s garden?
Leno4ka [110]

Answer:

63/50 meters^2 or in mixed number: 1 13/50 meters^2

Step-by-step explanation:

Area= length * width

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width= 3/10

21/5* 3/10 ( Multiply the denominators together). ( Multiply the numerators together).

21*3 / 5*10

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3 years ago
If the Quadratic functions for the equations are graphed, which is the widest?
Amanda [17]

y = ax^2

If the absolute value of a is <1 the graph is wider than when a = 1

If the absolute value of a is >1 the graph is narrow than when a = 1

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y = 2x^2

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3 years ago
explain how you can tell the difference between the half inch and quarter inch marks when measuring an object with a ruler
svlad2 [7]

Answer:

You will know it is an inch ruler because it will have 12 lines that denote inches on ... In the first inch, these marks will mark 1/4, 1/2, 3/4, and 1 ...

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3 years ago
For the matrices below. Find all (real) eigenvalues. <br><br> A= [7 9]<br> [0 9]
Jet001 [13]

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]

Using formula:

|A-\lambda \cdot I|= 0\\\\

\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\

\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\

8 0
3 years ago
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