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exis [7]
2 years ago
10

Students in an Introductory Statistics class at BYU-Idaho were studying prices of cold cereal at grocery stores in Rexburg. To g

et a sample of cold cereal prices, they went to Albertson's and rolled a die to decide which box from the left of the top shelf they would start on. They then recorded every 6th cereal after the first, moving from left to right down the shelves, recording the name, size, and price of each cereal in their sample. Is this study an experiment or an observational study, and why
Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
8 0

Answer: Observational study

Step-by-step explanation:

The study illustrated in the question is an observational study. It is referred to as an observational study, because in this case, the price of the individual cereals us not being controlled by the students. They've no control over it.

If it was an experiment, there'll have been a control group and the students will have control over the price. Also, the sampling methods used here is a systematic random sampling.

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Can someone help me please
Alborosie

Answer:

7

Step-by-step explanation:

Count the units (Squares) from the first point to the second and you will see that it is 7 units away.

6 0
3 years ago
Read 2 more answers
Olly drove 56 km from Liverpool to Manchester.
yawa3891 [41]

Answer:

57.073 km/h approx.

Step-by-step explanation:

Total distance from Liverpool to Sheffield

= 56 + 61 km

= 117 km

Time from Liverpool to Manchester

=56 km ÷ 70 km/h

=0.8 hours

Time from Manchester to Sheffield

=75 mins

=1.25 hours

Total time = 0.8 h + 1.25 h

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2 years ago
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Leto [7]

Answer:

Step-by-step explanation:

2222.88-1690.36=nope

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7 0
3 years ago
An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th
Ghella [55]

Answer:

A) The best way to picture this problem is with a probability tree, with two steps.

The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.

The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.

If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.

If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.

B) So a person can have a red marble and a blue marble in two ways:

1) Picking the red first and the blue last

2) Picking the blue first and the red last

C) P(R&B) = 3/5 = 60%

Step-by-step explanation:

C) P(R&B) = P(RB) + P(BR) = (2/5)*(3/4) + (3/5)*(2/4) = 3/10 + 3/10 = 3/5

3 0
2 years ago
Can someone please answer. There is one problem. There's a picture. Thank you!
allochka39001 [22]
\dfrac{60^o}{360^o}=\dfrac{1}{6}\\\\A_O=\pi\cdot4^2=16\pi\\\\Area\ of\ the\ shaded\ sector:\\\\A=\dfrac{1}{6}\cdot16\pi=\dfrac{8}{3}\pi\approx\dfrac{8}{3}\cdot3.14\approx8.4\\\\Answer:\boxed{8.4}
8 0
3 years ago
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