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bagirrra123 [75]

3 years ago

5

Please help.What are all the answers

1 answer:

andreyandreev [35.5K]3 years ago

5 0

Answer:

5.90=r, 6.67=can't see, 5.17=n, 5.34=o, 6.08=s, 6.83=can't see, 6.43=u, 5.01=m, 5.69=p

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Learning Task 1 4/625 11. 796 A. Simplify the radical expressions 1. V63 6. V24 2. 48 7. 781 3. 775 8. V128 4. 99 9. 340 5. 92 1

kompoz [17]

Question:

Simplify the radical expressions

$1.\ \sqrt{63$ $2.\ \sqrt{48$ $3.\ \sqrt{75$ $4.\ \sqrt{99$ $5.\ \sqrt{92$

$6.\ \sqrt[3]{24}$ $7.\ \sqrt[3]{81}$ $8.\ \sqrt{128}$ $9.\sqrt[3]{40}$ $10.\ \sqrt[3]{135}$

Answer:

$\sqrt{63}= 3 \sqrt7$

$\sqrt{48} = 4\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$\sqrt{99} = 3 \sqrt{11$

$\sqrt{92} = 2\sqrt{23$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$\sqrt{128} = 8 \sqrt{2}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

Step-by-step explanation:

$1.\ \sqrt{63$

Express 63 as 9 * 7

$\sqrt{63}= \sqrt{9 * 7$

Split:

$\sqrt{63}= \sqrt{9} * \sqrt7$

$\sqrt{63}= 3 * \sqrt7$

$\sqrt{63}= 3 \sqrt7$

$2.\ \sqrt{48$

Express 48 as 16 * 3

$\sqrt{48} = \sqrt{16*3}$

Split

$\sqrt{48} = \sqrt{16}*\sqrt{3}$

$\sqrt{48} = 4*\sqrt{3}$

$\sqrt{48} = 4\sqrt{3}$

$3.\ \sqrt{75$

Express 75 as 25 * 3

$\sqrt{75} = \sqrt{25*3}$

Split

$\sqrt{75} = \sqrt{25}*\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$4.\ \sqrt{99$

Express 99 as 9 * 11

$\sqrt{99} = \sqrt{9} * \sqrt{11}$

Split

$\sqrt{99} = 3 \sqrt{11$

$5.\ \sqrt{92$

Express 92 as 4 * 23

$\sqrt{92} = \sqrt{4} * \sqrt{23$

$\sqrt{92} = 2* \sqrt{23$

$\sqrt{92} = 2\sqrt{23$

$6.\ \sqrt[3]{24}$

Express 24 as 8 * 3

$\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}$

Express 8 as 2^3

$\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$7.\ \sqrt[3]{81}$

Express 81 as 27 * 3

$\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}$

Express 27 as 3^3

$\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$8.\ \sqrt{128}$

Express 128 as 64 * 2

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

$9.\sqrt[3]{40}$

Express 40 as 8 * 5

$\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}$

$\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$10.\ \sqrt[3]{135}$

Express 135 as 27 * 5

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

Express 27 as 3^3

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

4 0

3 years ago

Evaluate 3(a + b + c)2 for a = 2, b = 3, and c = 4.

Snowcat [4.5K]

Answer:

Step-by-step explanation:

3(2 + 3 + 4)^2

3(9)^2 = 3(81) = 243

6 0

3 years ago

Represent the following expressions as a power of the number a (a≠0):

Ivahew [28]

Answer:

Step-by-step explanation:

1) $(a^3)^{-2} = a^{-6}\\$

2) $(a^{-1} * a^{-2} )^{-3} = (a^{-1 + (-2)})^{-3} }=a^{-9}$

3) $((a^{2})^{-2})^{2}=(a^{-4})^{2}=(a^{-8})$

4) $(a*a)^{2} = (a^{2})^{2}=a^{4}$

8 0

3 years ago

Which of the following are solutions to the graph

jarptica [38.1K]

Answer:

F. $\displaystyle (2, 6)$

C. $\displaystyle (-1, 0)$

B. $\displaystyle (-2, -2)$

Step-by-step explanation:

You first need to find the linear equation<em> </em>[in <em>Slope-Intercept</em><em> </em><em>Form</em><em> </em>of course] of this graph, which is $\displaystyle y = 2x + 2.$ To do this, starting from the y-intercept of $\displaystyle (0, 2),$ you do $\displaystyle \frac{rise}{run}$ by either moving two blocks <em>south</em><em> </em>over one block <em>way</em><em> </em>or two blocks <em>north</em><em> </em>over<em> </em>one block <em>east</em> [<em>west</em><em> </em>and <em>south</em><em> </em>are negatives]. This will give you your <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] of 2.

* $\displaystyle y = mx + b → Slope-Intercept Formula$

I am joyous to assist you anytime.

3 0

3 years ago

Please answer this correctly without making mistakes

Kisachek [45]

Answer:

1st one, I think so. I'm pretty positive

4 0

4 years ago

Read 2 more answers