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Lesechka [4]
3 years ago
9

Describe the relationship between potential and kinetic energy

Chemistry
1 answer:
pashok25 [27]3 years ago
5 0

We know potential energy is position relative, and kinetic energy is motion relative. The primary relationship between the two is their ability to transform into each other. In other words, potential energy transforms into kinetic energy, and kinetic energy converts into potential energy, and then back again.

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How many moles are in 48 molecules of H2O? What is the given amount?
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A chemical reaction produces two new substances, and each product has a mass of 25 grams. What was the total mass of the reactan
hodyreva [135]
Well, according to the law of conservation of mass, the total mass of the reacting atoms must equal the total mass of the final rearranged products produced through the reaction. Assuming that both products are the only products produced, it would constitute the total matter produced, and since each product has a mass of 25 grams each. The total would be 50 grams. Thus the total mass of the reactants also would need to be 50 grams, as no matter is lost in a chemical reaction.
8 0
3 years ago
Which common material is an example of a polyamide?
Vlad1618 [11]

Nylon 6,6 is a common example of a polyamide.

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[-NH-(CH_2)_6-<u>NH-CO</u>-(CH_2)_4-CO-]_<em>n</em>

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The numbers in the name showow that there are six carbon atoms on either side of an amide linkage.

5 0
3 years ago
If 100.0g of nitrogen is reacted with 100.0g of hydrogen, what is the excess reactant? What is the limiting reactant? Show your
Drupady [299]

N₂ : limiting reactant

H₂ : excess reactant

<h3>Further explanation</h3>

Given

mass of N₂ = 100 g

mass of H₂ = 100 g

Required

Limiting reactant

Excess reactant

Solution

Reaction

<em>N₂+3H₂⇒2NH₃</em>

mol N₂(MW=28 g/mol) :

\tt mol=\dfrac{mass}{MW}=\dfrac{100}{28}=3.571

mol H₂(MW= 2 g/mol) :

\tt mol=\dfrac{100}{2}=50

A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactans become a limiting reactants

From the equation, mol ratio N₂ : H₂ = 1 : 3, so :

\tt \dfrac{3.571}{1}\div \dfrac{50}{3}=3.571\div 16.6

N₂ becomes a limiting reactant (smaller ratio) and H₂ is the excess reactant

5 0
3 years ago
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