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Ierofanga [76]
3 years ago
9

Olivia has a shoe box in the shape of a rectangular prism. She decorates 4 faces of the box,

Mathematics
2 answers:
Genrish500 [490]3 years ago
4 0

Taking the test rn, it’s 190 square inches.

Found the answer on another site. Worked fine, hope that helps

jekas [21]3 years ago
4 0

Answer:

440

Step-by-step explanation:

I HAVE I READY TOO AND IT’S KILLING ME

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Question 6. Geometry question.
kupik [55]

B. if two lines are perpendicular, then they intersect to form four right angles.

4 0
3 years ago
A farm has 15 rows of fruit trees with 7 trees in each row. The last 4 rows of trees are cherry trees. The remaining trees are o
siniylev [52]

Answer:

Total number of orange trees = 77 trees

Step-by-step explanation:

Given:

Total number of rows = 15

Total number of cherry rows = 4

Number of trees in each rows = 7

Find:

Total number of orange trees

Computation:

Total number of orange trees = [Total number of rows - Total number of cherry rows][Number of trees in each rows]

Total number of orange trees = [15 - 4]7

Total number of orange trees = [11]7

Total number of orange trees = 77 trees

6 0
3 years ago
Please help ASAP !! Via the photo below
cestrela7 [59]

Answer:

y-3 = -4 (x-1)

Step-by-step explanation:

y= -4x - 5

In slope-intercept form, they give us the slope, -4, and the y-intercept, -5 (we don't need for point-slope form).

Use the point (1,3) and substitute it into the equation.

Point-slope form: y-y1 = m(x-x1)

y-3 = -4 (x-1)

4 0
3 years ago
According to a report from a business intelligence company, smartphone owners are using an average of 22 apps per month. Assume
Ira Lisetskai [31]

Answer:

0.4332 = 43.32% probability that the sample mean is between 21 and 22.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

According to a report from a business intelligence company, smartphone owners are using an average of 22 apps per month.

This means that \mu = 22

Standard deviation is 4:

This means that \sigma = 4

Sample of 36:

This means that n = 36, s = \frac{4}{sqrt{36}}

What is the probability that the sample mean is between 21 and 22?

This is the p-value of Z when X = 22 subtracted by the p-value of Z when X = 21.

X = 22

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{22 - 22}{\frac{4}{sqrt{36}}}

Z = 0

Z = 0 has a p-value of 0.5.

X = 21

Z = \frac{X - \mu}{s}

Z = \frac{21 - 22}{\frac{4}{sqrt{36}}}

Z = -1.5

Z = -1.5 has a p-value of 0.0668.

0.5 - 0.0668 = 0.4332

0.4332 = 43.32% probability that the sample mean is between 21 and 22.

4 0
2 years ago
Use Definition 7.1.1. DEFINITION 7.1.1 Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = [inf
Alla [95]

f(t)=\begin{cases}-1&\text{for }0\le t

Write f(t) in terms of the unit step function u(t):

f(t)=-1(u(t)-u(t-1))+1u(t-1)=2u(t-1)-u(t)

where

u(t)=\begin{cases}1&\text{for }t\ge0\\0&\text{for }t

Then the Laplace transform of f(t), denoted F(s), is

F(s)=\displaystyle\int_0^\infty f(t)e^{-st}\,\mathrm dt

F(s)=\displaystyle2\int_1^\infty e^{-st}\,\mathrm dt-\int_0^\infty e^{-st}\,\mathrm dt

\implies F(s)=\dfrac{2e^{-s}}s-\dfrac1s=\dfrac{2e^{-s}-1}s

3 0
3 years ago
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