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pshichka [43]
3 years ago
10

In your own words define angle

Mathematics
2 answers:
LuckyWell [14K]3 years ago
7 0
An angle is two rays that lie on one plane, and both have the same endpoint. 

It could look like this :  ∠
Firlakuza [10]3 years ago
7 0
They both have the same end point like this <
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Answer:
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The container sells for 18.95. What is the unit rate in dollars per pack?
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$ 0.21 per pack

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<img src="https://tex.z-dn.net/?f=5%20%2B%20%20%5Cfrac%7Bx%20-%202%7D%7B3%7D%20%20%3D%20%20%5Cfrac%7Bx%20%2B%203%7D%7B8%7D%20" i
sammy [17]
First multiply each term by 24(the common denominator found by 8×3) to remove the fractions and make things easier.
24(5) + 24( \frac{x - 2}{3} ) = 24( \frac{x + 3}{8} )
This will give you,
120 + 8(x - 2) = 3(x + 3)
Then just continue to simplify and isolate the variable.
120 + 8x - 16 = 3x + 9
8x + 104 = 3x + 9
5x =  - 95
x =  - 19

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7
Katen [24]

\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

can be rewritten as

\rm \:  =  \: \dfrac{5 \times  { {(5}^{2} )}^{n + 1}  -  {5}^{2}  \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {( {5}^{2} )}^{n + 1} }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

And

\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

So, using this identity, we

\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

can be further rewritten as

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

4 0
2 years ago
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