All categories

2 years ago

Help me for brainlist find the volume

Mathematics

2 answers:

HACTEHA [7]2 years ago

8 0

Answer:

i think its b

Step-by-step explanation:

oksano4ka [1.4K]2 years ago

3 0

192 i think I’m not sure

You might be interested in

A furnace operates at 2,300°F.

Cloud [144]

Answer:

T = 2,300 + q × 250

6 0

3 years ago

What’s the slope of a line that passes through the points (-3,7) and (-3, 4)?

Dmitry_Shevchenko [17]

Answer: The slope should be infinity.

Step-by-step explanation: I hope this helps you!

4 0

3 years ago

Read 2 more answers

The area of a regular octagon is 25 cm2 what is the area with the sides five times as large

marin [14]

125 cm2 is the answer

6 0

3 years ago

Read 2 more answers

Please help me I will mark brainliest. I’m just double checking to make sure I got it correct

ycow [4]

Answer:

the length of c is 18.43909

Step-by-step explanation:

pythagorean therorem

3 0

2 years ago

4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25

jarptica [38.1K]

Answer with explanation:

$\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}$

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

$=e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}$

Multiplying both sides by Integrating Factor

$x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)$

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0

3 years ago