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Paladinen [302]
3 years ago
5

A triangle has two sides of length 12 and 13. What is the largest possible whole-number length for the third side?

Mathematics
1 answer:
Natali [406]3 years ago
3 0

Answer:

the 2 side of u have to subtract the numbers then add the numbers

Step-by-step explanation:

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There are two connected gears. One has 60 teeth and it makes 50 complete revolutions in a minute. How many complete revolutions
VikaD [51]

60/40 *50 = 75

75 revolutions

8 0
3 years ago
How do you know if alternate interior angles and alternate exterior angles have the same measure?
AnnZ [28]

Answer:

If the transversal cuts across parallel lines (the usual case) then alternate exterior angles have the same measure. So in the figure above, as you move points A or B, the two alternate angles shown always have the same measure.

Step-by-step explanation:

Hope this helps

5 0
3 years ago
In a set of 25 aluminum castings, four castings are defective (D), and the remaining twenty-one are good (G). A quality control
lianna [129]

Answer:

The sample space for selecting the group to test contains <u>2,300</u> elementary events.

Step-by-step explanation:

There are a total of <em>N</em> = 25 aluminum castings.

Of these 25 aluminum castings, <em>n</em>₁ = 4 castings are defective (D) and <em>n</em>₂ = 21 are good (G).

It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

{n\choose k}=\frac{n!}{k!(n-k)!}

Compute the number of samples that are possible as follows:

{25\choose 3}=\frac{25!}{3!\times (25-3)!}

      =\frac{25\times 24\times 23\times 22!}{3!\times 22!}\\\\=\frac{25\times 24\times 23}{3\times 2\times 1}\\\\=2300

The sample space for selecting the group to test contains <u>2,300</u> elementary events.

6 0
3 years ago
Find the lengths of the missing side . Simplify all radicals !!!<br> help mee!!!!!!
larisa86 [58]

Answer:

e = 13\sqrt{2}

f = 13\sqrt{2}

Step-by-step explanation:

The ∆ given is an isosceles ∆ with a right angle measuring 90°, and two congruent angles measuring 45° each.

Using trigonometric ratio formula, we can find the lengths of the missing side as shown below:

Finding e:

sin(\theta) = \frac{opp}{hyp}

sin(\theta) = sin(45) = \frac{\sqrt{2}}{2}

hyp = 26

opp = e = ?

Plug in the values into the formula

\frac{\sqrt{2}}{2} = \frac{e}{26}

Multiply both sides by 26

\frac{\sqrt{2}}{2}*26 = \frac{e}{26}*26

\frac{\sqrt{2}}{2}*26 = e

\frac{\sqrt{2}}{1}*13 = e

13\sqrt{2} = e

e = 13\sqrt{2}

Since side e is of the same length with side f, therefore, the length of side f = 13\sqrt{2}

3 0
3 years ago
Help me with this: How many residents were surveyed?
PtichkaEL [24]
22 you just count all of the dots
7 0
3 years ago
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