Help please if it’s wrong is okay ig no links

Please help!!!!!!!!!!!!!!!!!!!!!!! I'm NOT about to write all that out again. THANK YOU!!!!

NikAS [45]

Answer:

I am not able to see yo pics. sorry

Step-by-step explanation:

4 0

3 years ago

The top of the cylindrical can shown below has a diameter of 7 centimeters (cm).

Sidana [21]

Answer:

Circumference of the can is 21.98 cm.

Step-by-step explanation:

Since, top of the cylinder can shown in the figure is in the shape of a circle

Circumference of a circle is given by the formula,

Circumference 'C' = π × Diameter

Where r = radius of the circle

Therefore, circumference of a circle with diameter 7 centimeters will be,

C = 7π

= 7 × 3.14

= 21.98 cm

Therefore, circumference of the can is 21.98 cm.

5 0

3 years ago

Jane babysits for $8 per hour. She earned $240 last week. This equation represents the number of hours, h, Jane babysat last wee

Tatiana [17]

Answer:

30 Hours

Step-by-step explanation:

8h=240

240÷8=30

8 0

3 years ago

Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6

horsena [70]

Answer:

$x^{4} -18x^{3}+104x^{2} -172x-100$

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:

$\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))( x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\$

7 0

3 years ago

Cassie has test grades of 62, 85 and 89 on the first three tests in herpre-algebra class. What are the possible scores she can m

Vsevolod [243]

Explanation:

The test grade for 1st three tests = 62, 85, 89

Let the fourth test score = x

The result we hoping to get is grade B.

Let's find the average of the four test score

$\text{Average = }\frac{Su\text{ m of all test score}}{nu\text{mber of test score}}$ $\begin{gathered} s\text{ um of test scores = 62 + 85 + 89 + x} \\ nu\text{mber of test score = 4} \\ \frac{\text{62 + 85 + 89 + x}}{4}=\text{ Average} \end{gathered}$ $\begin{gathered} A\text{ grade B represents atleast 80} \\ \text{Atleast represents }\ge \\ \frac{\text{62 + 85 + 89 + x}}{4}\text{ }\ge\text{ 80} \\ \frac{\text{236 + x}}{4}\text{ }\ge\text{ 80} \end{gathered}$ $\begin{gathered} \text{236 + x }\ge\text{ }80(4) \\ \text{236 + x }\ge\text{ }320 \\ \text{subtract }236\text{ from both sides:} \\ 236\text{ - 236 + x }\ge\text{ }320\text{ - 23}6 \\ x\text{ }\ge\text{ 84} \end{gathered}$

This means Cassie needs to score 84 or more to get a grade of B

In ineq

3 0

1 year ago