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Sauron [17]
1 year ago
12

Just Need A Few Questions Answered To Finish My Quiz, Any Help Would Be Much Appreciated.

Mathematics
1 answer:
kvv77 [185]1 year ago
8 0

Given the triangle

PQR

with points

P(8,0)

Q(6,2)

R(-2,-4)

And the triangle

P'Q'R'

with points

P'(4,0)

Q'(3,1)

R'(-1,-2)

Part A. Scale factor

Using the vertex

P( 8, 0)

P'(4,0)

the dilatation factor is given by

\frac{4}{8}=\frac{1}{2}

The triangle has a dilatation factor of 1/2

Part B:

P''Q''R'' after using P'Q'R' reflected about the y axis

to make a reflection over the y axis

coordinates (x,y) turn into coordinates (-x,y)

as follows

P^{\prime}(4,0)\rightarrow P^{\prime\prime}(-4,0)Q^{\prime}(3,1)\rightarrow Q^{\prime\prime}(-3,1)R^{\prime}(-1,-2)\rightarrow R^{\prime\prime}(1,-2)

Then triangle P''Q''R'' has coordinates

P''(-4,0)

Q''(-3,1)

R''(1,-2)

Part C:

PQR is congruent to P''Q''R''?

Congruent triangles are triangles that have the same size and shape. This means that the corresponding sides are equal and the corresponding angles are equal.

Then the triangles are not congruent

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(n^3 +67² + 4n - 2)/(n + 1)
Alla [95]

Answer:

(n^3 + 4 n + 4487)/(n + 1)

Step-by-step explanation:

Simplify the following:

(n^3 + 4 n - 2 + 67^2)/(n + 1)

| | 6 | 7

× | | 6 | 7

| 4 | 6 | 9

4 | 0 | 2 | 0

4 | 4 | 8 | 9:

(n^3 + 4 n - 2 + 4489)/(n + 1)

Grouping like terms, n^3 + 4 n - 2 + 4489 = n^3 + 4 n + (4489 - 2):

(n^3 + 4 n + (4489 - 2))/(n + 1)

4489 - 2 = 4487:

Answer: (n^3 + 4 n + 4487)/(n + 1)

5 0
3 years ago
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Ronch [10]

Answer:

<h2> </h2><h2>{1024t}^{5}  - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2}   + 1620t-  243</h2>

Step-by-step explanation:

<h3><em><u>Question</u></em><em><u>:</u></em><em><u>-</u></em></h3>
  • To find the Binomial theorem form of \bold{(4t-3)^{5}}
<h3><em><u>As</u></em><em><u> </u></em><em><u>we</u></em><em><u> </u></em><em><u>know</u></em><em><u>:</u></em><em><u>-</u></em></h3>

<em>As</em><em> </em><em>in</em><em> </em><em>Bin</em><em>omial</em><em> </em><em>theorem</em><em> </em><em>:</em><em>-</em>

  • {(x - y)}^{5}  =  {x}^{5}  - 5 {x}^{4} y + 10 {x}^{3}  {y}^{2}  - 10 {x}^{2}  {y}^{3}  + 5x {y}^{4}  -  {y}^{5}
<h3><em><u>Solution</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em></h3>

= {(4t - 3)}^{5}

  • <em>Hence</em><em>,</em><em> </em><em>on</em><em> </em><em>using</em><em> </em><em>the</em><em> </em><em>Binomial</em><em> </em><em>theorem</em><em>,</em><em> </em>

=  {(4t)}^{5}  - 5 {(4t)}^{4} (3)+ 10 {(4t)}^{3}  {(3)}^{2}  - 10 {(4t)}^{2}  {(3)}^{3}  + 5(4t) {(3)}^{4}  -  {(3)}^{5}

  • <em>On</em><em> </em><em>formatting</em><em> </em>

=  {1024t}^{5}  - 5 ({256t}^{4} )(3)+ 10 ({64t}^{3} ) (9 ) - 10 ({16t}^{2}  )(27)  + 5(4t) (81) -  243

  • <em>On</em><em> </em><em>further</em><em> </em><em>formatting</em><em>.</em><em> </em>

=  {1024t}^{5}  - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2}   + 1620t-  243

<em><u>Hence</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>required</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em>

{1024t}^{5}  - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2}   + 1620t-  243

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irakobra [83]

Answer:

2

Step-by-step explanation:

as you have to add them and divide and do probability trees

4 0
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Question 18
Svetlanka [38]

Answer:

Step-by-step explanation:

J and K are equal

8x - 23 = 6x + 11            Add 23 to both sides

8x = 6x + 11 + 23           Combine the right

8x = 6x + 34                  Subtract 6x from both sides

8x - 6x = 34                   Combine the left

2x = 34                           Divide by 2

x = 34/2

x = 17

=================================

M and L are both supplementary to J and K respectively.

J = 8x - 23

J = 8*17 - 23

J = 136-23

J = 113

K = 113

===================================

M + 113 = 180

M = 180 - 113

M = 67

L = 67

5 0
3 years ago
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kipiarov [429]
Here is ur answer
0.357142857142857
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