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shusha [124]
3 years ago
13

What is the vertex of the graph of the function below? y=x^2-10x+24

Mathematics
2 answers:
adoni [48]3 years ago
4 0
\bf \textit{vertex of a vertical parabola, using coefficients}
\\\\
\begin{array}{llcccl}
y = & 1x^2& -10x& +24\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\qquad 
\left(-\cfrac{ b}{2 a}\quad ,\quad   c-\cfrac{ b^2}{4 a}\right)
\\\\\\
\left( -\cfrac{-10}{2(1)}~~,~~24-\cfrac{(-10)^2}{4(1)} \right)\implies \left(5~~,~~24-25  \right)\implies (5~,~-1)
cupoosta [38]3 years ago
3 0
The vertex of the equation is (5,-1). Rewrite in standard form. (h,k)
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