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gladu [14]
3 years ago
7

Evaluate the expression y-x+ z for x = 4.6, y=6, and z=0.59

Mathematics
1 answer:
nignag [31]3 years ago
8 0

Answer:

<h2><em>1</em><em>.</em><em>9</em><em>9</em></h2>

<em>Solution,</em>

<em>y-x+</em><em>z</em>

<em>=</em><em>6</em><em>-</em><em>4</em><em>.</em><em>6</em><em>+</em><em>0</em><em>.</em><em>5</em><em>9</em>

<em>=</em><em>6</em><em>+</em><em>0</em><em>.</em><em>5</em><em>9</em><em>-</em><em>4</em><em>.</em><em>6</em>

<em>=</em><em>6</em><em>.</em><em>5</em><em>9</em><em>-</em><em>4</em><em>.</em><em>6</em>

<em>=</em><em>1</em><em>.</em><em>9</em><em>9</em>

<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

<em>good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

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Answer:

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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Central Limit Theorem

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For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean $39725 and standard deviation $7320.

This means that \mu = 39725, \sigma = 7320

Sample of 125

This means that n = 125, s = \frac{7320}{\sqrt{125}}

The probability that the sample mean would be at least $39000 is about?

This is 1 subtracted by the pvalue of Z when X = 39000. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{39000 - 39725}{\frac{7320}{\sqrt{125}}}

Z = -1.11

Z = -1.11 has a pvalue of 0.1335

1 - 0.1335 = 0.8665

The probability that the sample mean would be at least $39000 is of 0.8665 = 86.65%.

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