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Ratling [72]
4 years ago
8

Find the simplified form of each expression (4/7y^5)^2

Mathematics
1 answer:
Natasha2012 [34]4 years ago
7 0
( \frac{4}{7y^5} )^2
\frac{4^2}{7^2y^10}
\frac{16}{49y^10}
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3 years ago
Find the constant of variation for the quadratic variation. 6y=4x^2
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\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
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6y=4x^2\implies y=\cfrac{4x^2}{6}\implies y=\cfrac{2x^2}{3}\implies y=\stackrel{k}{\cfrac{2}{3}}x^2
7 0
3 years ago
Pls help me with this
OlgaM077 [116]

Answer:

  1/(x^(17/12)y^(5/3))

Step-by-step explanation:

We assume you want to simplify the expression. The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(bc)

  1/a^b = a^-b

Using these "all at once", we can add up the exponents of each of the variables:

  x^(-2/3 -2·0 -(1/2)(3/2))·y^(-2/3-(1/2)·2) = x^(-2/3-3/4)y^(-2/3-1)

  = x^(-17/12)y^(-5/3)

  = \dfrac{1}{x^{\frac{17}{12}}y^{\frac{5}{3}}}

4 0
4 years ago
Find the area of the circle to the nearest tenth. 12 in
Alexus [3.1K]

Answer:

The answer is B

I had search that up before

6 0
3 years ago
The table and scatter plot below show the number of hits and runs Tyler's baseball team got in each of 12 tournament games.
agasfer [191]

The correct statements are:

  • There is a positive linear equation between the number of hits and the scores
  • The point (7,13) is an outlier.
  • If the trend continues, for a game when Tyler's team gets 20 hits, the number of runs scored would be greater than 10 hits.

<h3>What are the correct statements?</h3>

An outlier is a number that is way smaller or way larger than that of other numbers in a data set. On a trend line, an outlier would be far from the trendline.

A positive linear relationship is when as one of the variables increase, the other variable also increases and the trendline is a straight line that is upward sloping.

To learn more about outliers, please check: brainly.com/question/27197311

#SPJ1

3 0
3 years ago
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